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2 years ago

What is the volume of the cone?

Mathematics

1 answer:

Vesnalui [34]2 years ago

4 0

Volume of a cone

V = 1/3 *pi* r^2 *h

we know the diameter d=22

the radius r = 1/2 d = 1/2 (22) = 11

substitute in

V = 1/3 * pi * 11^2 * 22

V = 1/3 * pi * 121 * 22

V = 2662/3 * pi

pi is approximately 3.14

V =2787.639882 yd^3

Rounding

V = 2787.64 yd^3

Choice B

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Determine if the two lines with the given slope are parallel, perpendicular, or neither. Circle your

Sati [7]

Answer:

As the lines are neither parallel nor perpendicular.

Therefore, the correct answer is ''neither''.

Hence, option C is correct.

Step-by-step explanation:

Given

m₁ = 3/2

m₂ = -3/2

We know that when two lines are parallel, they have equal slopes

But

m₁ ≠ m₂

3/2 ≠ -3/2

As the m₁ and m₂ are not equal.

Hence, the lines are not parallel.

We know that when two lines are perpendicular, the product of their slopes is -1.

Let us check the product of two slopes m₁ and m₂

m₁ × m₂ = 3/2 × -3/2

= -9/4

= -2.25

m₁ × m₂ ≠ -1

Thus, the lines are not perpendicular.

Conclusion:

As the lines are neither parallel nor perpendicular.

Therefore, the correct answer is ''neither''.

Hence, option C is correct.

8 0

2 years ago

Pleasee help!!! (brainlest) (15 points)

USPshnik [31]

-1400 + 800 - 350 = - 950 meters

5 0

3 years ago

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Rose picked 18 tulips and 20 lilies.She divided the flowers into groups so that the same number of tulips and lilies were in eac

RSB [31]

Anwser: 18=9 groups and 20= 10 groups

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3 years ago

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The linear equation of the initial (red ) incline would be y = __x +__

RideAnS [48]

Answer:

$y=\underline {1.5}x+\underline 0$

Step-by-step explanation:

From the graph,

The initial red incline is a straight line passing through the origin.

So, a straight line passing through the origin is of the form:

$y=mx+0$

Where, 'm' is the slope.

Now, the slope of a given as the change in y value to change in x value.

Consider the two end points of the red line (0, 0) and (4, 6).

The slope with two points $(x_1,y_1)\ and\ (x_2,y_2)$ on the line is given as:

$m=\frac{(y_2-y_1)}{(x_2-x_1)}$

Plug in $x_1=0,y_1=0,x_2=4,y_2=6$ . Therefore, slope is:

$m=\frac{6-0}{4-0}\\m=\frac{6}{4}=1.5$

Hence, the equation of the initial red incline is:

$y=\underline {1.5}x+\underline 0$

3 0

3 years ago

Help . will mark best answer

ZanzabumX [31]

answer: infinitely many :)

5 0

3 years ago