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4 years ago

Solve for x in the equation y^2 + 2x + 1 = 17.

Mathematics

2 answers:

Grace [21]4 years ago

4 0

Answer:

Step-by-step explanation:

So your equation is actually x^2+2x+1=17

Left hand side is already set for rewriting it as a perfect square

So you have actually that (x+1)^2=17

Now you just take square root of both sides

x+1=(pm) sqrt(17) (pm) means plus or minus

x=-1 (pm) sqrt(17) I subtracted 1 on both sides

Furkat [3]4 years ago

3 0

Answer:

x = −1 ± √17

Hope this helps and have a nice day! :)

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We can write any number n in the form $e^{\ln(n)}$ , since $e^x$ and $\ln(x)$ are inverse functions, so that

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3 years ago

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Step-by-step explanation:

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Solve for x in the equation y^2 + 2x + 1 = 17.​

Solve for x in the equation y^2 + 2x + 1 = 17.