Question

Solve for x in the equation y^2 + 2x + 1 = 17.​

Answer 1

Answer:

B

Step-by-step explanation:

So your equation is actually x^2+2x+1=17

Left hand side is already set for rewriting it as a perfect square

So you have actually that (x+1)^2=17

Now you just take square root of both sides

x+1=(pm) sqrt(17)                        (pm) means plus or minus

x=-1 (pm) sqrt(17)                         I subtracted 1 on both sides

B

Answer 2

Answer:

x = −1 ± √17

Hope this helps and have a nice day! :)