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Ede4ka [16]
3 years ago
10

Calculation the ionisation energy of rubidium per atom, if light of wavelength 5.84 × 10^-8 m produces electrons with a speed of

2.450 × 10^6 ms^1 .
Chemistry
1 answer:
Masja [62]3 years ago
3 0
E = energy in the light rays = h ν = h c /λ = 6.67 * 10×⁻³⁴ * 3 * 10⁸ / (5.84*10⁻⁸) J = 3.42 * 10⁻18 JKinetic energy of electrons = 1/2 m u^2 = 1/2 * 9.1 * 10⁻³¹ * (2.45 * 10⁶)² J = 2.73 * 10⁻¹⁸ J The ionization energy = (3.42 - 2.73) * 10⁻¹⁸ J = 6.9 * 10⁻¹⁹ J
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What is the volume at stp of 720.0 ml of a gas collected at 20.0 °c and 3.00 atm pressure?
MArishka [77]
Combined gas law is 
       PV/T = K (constant)

P = Pressure
V = Volume
T = Temperature in Kelvin

For two situations, the combined gas law can be applied as,
     P₁V₁ / T₁ = P₂V₂ / T₂

P₁ = 3.00 atm                                     P₂ = standard pressure = 1 atm
V₁ = 720.0 mL                                    T₂ = standard temperature = 273 K
T₁ = (273 + 20) K = 293 K
  
By substituting,
 3.00 atm x 720.0 mL / 293 K = 1 atm x V₂ / 273 K
                                          V₂ = 2012.6 mL

hence the volume of gas at stp is 2012.6 mL
5 0
3 years ago
Calculate the density of chlorine gas in g/l, at stp.
vichka [17]
The Answer would be e: 3.2 g/L 

<span>At STP : p = 1 atm and T = 273.15 K 
molar mass Cl2 = 70.906 g/mol 

d = molar mass x p/RT = 70.906 x 1 atm / 0.08206 x 273.15=3.16 g/L</span>
8 0
4 years ago
Consider two equal-volume flasks of gas at the same temperature and pressure. One gas, oxygen, has a molecular mass of 32. The o
san4es73 [151]

Answer: The ratio of the number of oxygen molecules to the number of nitrogen molecules in these flasks is 1: 1

Explanation:

According to avogadro's law, equal volumes of all gases at same temperature and pressure have equal number of moles.

According to avogadro's law, 1 mole of every substance contains avogadro's number 6.023\times 10^{23} of particles.

Thus as oxygen and nitrogen are at same temperature and pressure and are in equal volume flasks , they have same number of moles and thus have same number of molecules.

The ratio of the number of oxygen molecules to the number of nitrogen molecules in these flasks is 1: 1

3 0
3 years ago
How much heat is absorbed by a 112.5 g sample of water when it is heated from 12.5 °C to 9°C? (Specific heat capacity of water i
Oduvanchick [21]

Answer:

–1647.45 J

Explanation:

From the question given above, the following data were obtained:

Mass (M) = 112.5 g

Initial temperature (T₁) = 12.5 °C

Final temperature (T₂) = 9°C

Specific heat capacity (C) = 4.184 J/g°C

Heat (Q) absorbed =?

Next, we shall determine the change in temperature. This can be obtained as follow:

Initial temperature (T₁) = 12.5 °C

Final temperature (T₂) = 9°C

Change in temperature (ΔT) =?

ΔT = T₂ – T₁

ΔT = 9 – 12.5

ΔT = –3.5 °C

Finally, we shall determine the heat absorbed. This can be obtained as follow:

Mass (M) = 112.5 g

Change in temperature (ΔT) = –3.5 °C

Specific heat capacity (C) = 4.184 J/g°C

Heat (Q) absorbed =?

Q = MCΔT

Q = 112.5 × 4.184 × –3.5

Q = –1647.45 J

5 0
3 years ago
Differentiate between satured and unsatured fats
olga_2 [115]

Answer:

...

Explanation:

in saturated fats there is no double bond between the acids and are tightly packed and unsaturated fats arent tight and loosely packed/put together

saturated- solid at room temperature

unsaturated= liquid at room temperature

two types of unsaturated fats, Polyunsaturated fats and Monounsaturated fats

6 0
3 years ago
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