If 20.0g of water at 56.2℃ absorbs 195 J of heat, what is the final temperature? *
1 answer:
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<h3>Further explanation</h3>Aldehydes are alkane-derived compounds containing carbonyl groups (-CO-) where one bond binds to an alkyl group while another binds to a hydrogen atom.
The general structure is R-CHO with the molecular formula :
Naming is generally the same as the alkane by replacing the suffix with -al
Butanal or butyraldehyde is an aldehyde which has 4 C atoms
Inside the structure there are 3 atoms involved in bonding:
- 1. Atom C with 4 valence electrons, requires 4 electrons to reach the octet
- 2. Atom O with 6 valence electrons, requires 2 electrons to reach the octet
- 3. Atom H with 1 valence electron, requires 1 electron to reach a duplet
In describing Lewis's structure the steps that can be taken are:
- 1. Count the number of valence electrons from atoms in a molecule
- 2. Give each bond a pair of electrons
- 3. The remaining electrons are given to the atomic terminal so that an octet is reached
- 4. The remaining electrons that still exist in the central atom
- 5. If the central atom is not yet octet, free electrons are drawn to the central atom to form double bonds
In the Butanal structure (C₄H₈O) there is 1 double bond of the functional group (-CHO) between the C atom and the O atom
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Keywords: butanal, aldehyde, Lewis structure, a valence electron
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Anode :
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Your given question is quite incomplete here is complete question.
A voltaic cell is based on the reduction of _ Agt(aq) to Ag(s) and the oxidation of Sn(s) to Sn2+(aql) : Part 1 Include the phases of all species in the chemical equation: (aqh Anode: Sn(s) Sn?+ (aq)
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Answer:
4.8 grams of H₂ will be produced if 175g of HCI are allowed to react completely with sodium
Explanation:
By stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction) you can see that the following amounts in moles of each compound react and are produced:
- HCl: 2 moles
- Na: 1 mole
- NaCl: 2 moles
- H₂: 1 mole
You know the following masses of each element:
- H: 1 g/mole
- Cl: 35.45 g/mole
- Na: 23 g/mole
So, the molar mass of each compound participating in the reaction is:
- HCl: 1 g/mole + 35.45 g/mole= 36.45 g/mole
- Na: 23 g/mole
- NaCl: 23 g/mole + 35.45 g/mole= 58.45 g/mole
- H₂: 2* 1 g/mole= 2 g/mole
Then, by stoichiometry of the reaction, the following amounts in grams of each of the compounds participating in the reaction react and are produced:
- HCl: 2 moles* 36.45 g/mole= 72.9 g
- Na: 1 mole* 23 g/mole= 23 g
- NaCl: 2 moles* 58.45 g/mole= 116.9 g
- H₂: 1 mole* 2 g/mole= 2 g
So, a rule of three applies as follows: if by stoichiometry, when reacting 72.9 grams of HCl 2 grams of H₂ are formed, when reacting 175 grams of HCl how much mass of H₂ will be formed?
mass of H₂= 4.8 g
<u><em>4.8 grams of H₂ will be produced if 175g of HCI are allowed to react completely with sodium</em></u>