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Zolol [24]
3 years ago
11

Determine whether the lines are parallel, perpendicular or neither: Line 1:4y−12=3x Line 2:2y−1.5x=−14

Mathematics
1 answer:
Kamila [148]3 years ago
6 0

For this case we have that by definition, the equation of a line in the slope-intersection form is given by:

y = mx + b

Where:

m: It's the slope

b: It is the cut-off point with the y axis

We manipulate the expressions to model them in the pending-intersection form

Line 1:

4y-12=3x\\4y=3x+12\\y=\frac{3}{4}x+\frac{12}{4}\\y=\frac{3}{4}x+3\\y=0.75x+3

Line 2:

2y - 1.5x = -14\\2y = 1.5x-14\\y = \frac {1.5} {2} x- \frac {14} {2}\\y = \frac {1.5} {2} x-7\\y = 0.75x-7

By definition, we have that if two lines are parallel then their slopes are equal. It is observed that the slopes of both lines are equal, so the lines are parallel.

ANswer:

The lines are parallel

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Can yall help me figure out what 1/3+3/9
devlian [24]

Answer:

6/9 = 2/3

Step-by-step explanation:

1/3 = 3/9

3/9 = 3/9

3/9 + 3/9= 6/9 = 2/3

7 0
3 years ago
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The exponential decay graph shows the expected depreciation for a new boat, sell g for $3500, over 10 years.
Alisiya [41]
Okay, the exponential function is
g = a^{x}
The start price of it in t=0 is 3,500, as we can see on the graph. Then, the function becomes
g = 3500^{x}
Let's see at t=2, where the price is g=2000:
2000 =  3500^{x}
Take natural logarithm:
ln 2000 = ln  3500^{x}
x*ln 3500 = ln 2000
x = \frac{ln 2000}{ln 3500} = 0.93
So, the difference between t=0 and t=2 is
x_{t=0}  -  x_{t=2}  = 1 - 0.93 = 0.07
And then we get the change of x in one year equal to 0.035.
So, the final equation is
g =  3500^{1-0.035t}
You can insert any t and see that it is correct, for example t=7
8 0
3 years ago
Someone help!!! What is 4/5+7/8
noname [10]
Im pretty sure the answer is 1.675
5 0
3 years ago
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<img src="https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B5x%2F8y%7D" id="TexFormula1" title="\sqrt[4]{5x/8y}" alt="\sqrt[4]{5x/8y}" al
Furkat [3]

Answer:  \frac{\sqrt[4]{10xy^3}}{2y}

where y is positive.

The 2y in the denominator is not inside the fourth root

==================================================

Work Shown:

\sqrt[4]{\frac{5x}{8y}}\\\\\\\sqrt[4]{\frac{5x*2y^3}{8y*2y^3}}\ \ \text{.... multiply top and bottom by } 2y^3\\\\\\\sqrt[4]{\frac{10xy^3}{16y^4}}\\\\\\\frac{\sqrt[4]{10xy^3}}{\sqrt[4]{16y^4}} \ \ \text{ ... break up the fourth root}\\\\\\\frac{\sqrt[4]{10xy^3}}{\sqrt[4]{(2y)^4}} \ \ \text{ ... rewrite } 16y^4 \text{ as } (2y)^4\\\\\\\frac{\sqrt[4]{10xy^3}}{2y} \ \ \text{... where y is positive}\\\\\\

The idea is to get something of the form a^4 in the denominator. In this case, a = 2y

To be able to reach the 16y^4, your teacher gave the hint to multiply top and bottom by 2y^3

For more examples, search out "rationalizing the denominator".

Keep in mind that \sqrt[4]{(2y)^4} = 2y only works if y isn't negative.

If y could be negative, then we'd have to say \sqrt[4]{(2y)^4} = |2y|. The absolute value bars ensure the result is never negative.

Furthermore, to avoid dividing by zero, we can't have y = 0. So all of this works as long as y > 0.

3 0
3 years ago
What is the equation of the line on the graph with points (-2,2) and (-2,-3)
nika2105 [10]

Answer:

x=-2

Step-by-step explanation:

Given points are (-2,2) and (-2,-3).

Now we need to find equation of the line passing through the given points.

So let's begin by finding slope

m=\frac{\left(y_2-y_1\right)}{\left(x_2-x_1\right)}=\frac{\left(-3-2\right)}{\left(-2-\left(-2\right)\right)}=\frac{\left(-5\right)}{\left(-2+2\right)}=-\frac{5}{0}

which is undefined. That means graph of the line must be vertical as you can see that in given points, x-value is not changing.

Equation of vertical line is given by x=k where k is the fixed value of x-coordinate.

x-coordinate is -2 in given points.

Hence final equation is x=-2.

4 0
3 years ago
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