5 7/8 is 47/8
Because,
You multiply 5 and 8 and then add 7, then you keep the denominator.
Answer:
2x^20
Step-by-step explanation:
<u>Answer:</u>
The value of f(x) =
when x=3 is 19, hence the correct option is ‘d’.
<u>Solution:</u>
A two degree polynomial equation is given in the question.
The equation is:

We need <em>to find the value of f(x) when the value of x is 3.
</em>
To solve a question like this we have to substitute the given value of x in the given equation and then simplify it.
Now let's substitute the value of x in the given equation.

First we square the number 3 and then multiply it with 2 and then add 1.
This is done because of the BODMAS rule, in which multiplication is given higher preference as compared to addition.
On solving the equation we get,
F(x)=2×9+1
F(x)=18+1
F(x)=19.
Therefore the value of f(x) when x=3 is 19.
Hence the correct option is ‘d’.
City code says you need to have a total of at least 54 toilet stalls, but each bathroom can only have 6 stalls.
So, Let the number of bathrooms to be built be = x
Number of toilet stalls needed = 54
Number of stalls each bathroom can have = 6
So, the number of bathrooms to be built are =



Hence, one must build 9 bathrooms with 6 stalls each.
Answer:
Equation 3
Step-by-step explanation:
An identity is, simply put, an equation that is always true. 1 = 1, 2 = 2, and x = x are all examples of identities, as there's no case in which 1 ≠ 1, 2 ≠ 2, and x ≠ x. Essentially, if we can manipulate and equation so that we end up with the same value on either side, we've found an identity. Let's run through and try to solve each of these equations to see which one fulfills that condition:
8 - (6v + 7) = -6v - 1
8 - 6v - 7 = -6v - 1
1 - 6v = -6v - 1
1 = -1
This is clearly untrue. Moving on to the next equation:
5y + 5 = 5y - 6
5 = -6
Untrue again. Solving the third:
3w + 8 - w = 4w - 2(w - 4)
2w + 8 = 4w - 2w + 8
2w + 8 = 2w + 8
If we created a new variable z = 2w + 8, we could rewrite this equation as
z = z, <em>which is always true</em>. We can stop here, as we've now found that equation 3 is an identity.