Find three consecutive interferes whose sum is 96
1 answer:
Answer:
31, 32, 33
Step-by-step explanation:
x + x + 1 +x + 2 = 96
3x + 3 = 96
-3 -3
3x = 93
/3 /3
x = 31
31 is the first number, so since they’re consecutive, the second two numbers are 32 and 33.
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1$ + 1.5$ = 2.5$ ?
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W=-9
Explanation: 3w=-27
Divide 3 from -27
-27 divided by 3 = -9
Leaf #2 because 27 and 23 are closest to 30
Answer:
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Step-by-step explanation:
hopes this helps you