Find three consecutive interferes whose sum is 96
       
      
                
     
    
    
    
    
    1 answer:
            
              
              
                
                
Answer:
31, 32, 33
Step-by-step explanation:
x + x + 1 +x + 2 = 96
3x + 3 = 96
       -3    -3
3x = 93
/3     /3
x = 31
31 is the first number, so since they’re consecutive, the second two numbers are 32 and 33.
 
                                
             
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I would say 32 <span>• 3/4 or 32* 3/4 
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W=-9
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Divide 3 from -27
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Leaf #2 because 27 and 23 are closest to 30
        
             
        
        
        
Answer:
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Step-by-step explanation:
hopes this helps you