3 years ago

Find three consecutive interferes whose sum is 96

Mathematics

1 answer:

Ronch [10]3 years ago

6 0

Answer:

31, 32, 33

Step-by-step explanation:

x + x + 1 +x + 2 = 96

3x + 3 = 96

-3 -3

3x = 93

/3 /3

x = 31

31 is the first number, so since they’re consecutive, the second two numbers are 32 and 33.

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For this case we have the following multiplication:

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Answer:

Jack's strategy is:

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