your answer is 0.00833M the volume was converted into liters
NaOH(aq)+HCl(aq)→NaCl(aq)+H2O(l)
Using the molarity equation, we can find the number of moles of HCl that reacted:
molarity=mol soluteL soln
mol solute=(molarity)(L soln)
mol HCl=(0.105molL)(0.0250L)=0.00263 mol HCl
(volume converted to liters)
Now, using the coefficients of the chemical reaction, we can determine the number of moles of NaOH that reacted:
0.00263mol HCl(1lmol NaOH1mol HCl)=0.00263 mol NaOH
Lastly, we'll use the molarity equation (using given volume of NaOH soln) again to determine the molarity of the sodium hydroxide solution:
molarity=mol soluteL soln
I would say that you would need 12 to have it be equal for this reaction to happen. I hope that this helped. :)
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