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Arlecino [84]
3 years ago
9

A soup can has a diameter of 8 cm and a height of 12 cm . What is the volume of the soup can?

Mathematics
2 answers:
podryga [215]3 years ago
8 0

Answer:

602.88

Step-by-step explanation:

Romashka-Z-Leto [24]3 years ago
3 0
Volume = Pi × radius squared × height

Radius = Diameter ÷ 2
= 8 ÷ 2
= 4 cm

Volume = Pi × 4 squared × 12
= Pi × 16 × 12
= 603.1857895...
= 603.19 cm cubed

Note : Pi is approximately equal to 3.14

Please feel free to ask if you have any questions
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How many times greater than √2 is√32?<br><br> Can anybody help out here?
Anarel [89]

Answer:

4

Step-by-step explanation:

Root32= 4×root2

Root32 is 4 times greater than root2

Pls mark as brainliest

5 0
3 years ago
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I need help showing my work for 67.42 \4
pychu [463]
If the image does not open, just let me know 

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3 years ago
The graph shows the cost, C, of sending m text messages. What is the cost per message?
Travka [436]

Answer:

C.$0.15 I TOOK IT ON STUDY ISLAND

Step-by-step explanation:

First, you want to find an exact point on the graph.  What I mean by this is you want to go somewhere on the graph where the line goes through an exact y and x value.

Second, you want to figure out where this x and y value are.  Where the graph first goes through two points is at (20, 3).

Third, you want to figure out what the 20 and the 3 mean.  20 is the number of messages and 3 is the dollar amount.

Finally, to calculate the amount of money per message, you divide the dollar amount (3) by the number of messages (20).  So, you have 3/20.  After this, simplify 3/20 to get 0.15, or 15 cents per message.

3 0
3 years ago
Which represents the solution of –9.5 + 6x ≥ 42.1 using interval notation?
OlgaM077 [116]
Hello : 
<span>–9.5 + 6x ≥ 42.1
6x </span>≥ 42.1 + 9.5
6x ≥ 51.6
x ≥ 51.6/6
x ≥ 8.6
using interval notation: <span>[8.6  ; +∞[ </span>
5 0
3 years ago
out of some students appeared in an examination 80% passed in mathematics 75% passed in english and 5% failed in both subjects i
Advocard [28]

Answer:

5000 students appeared in the examination.

Step-by-step explanation:

We solve this question using Venn probabilities.

I am going to say that:

Event A: Passed in Mathematics

Event B: Passed in English.

5% failed in both subjects

This means that 100 - 5 = 95% pass in at least one, which means that P(A \cup B) = 0.95

80% passed in mathematics 75% passed in english

This means that P(A) = 0.8, P(B) = 0.75

Proportion who passed in both:

P(A \cap B) = P(A) + P(B) - P(A \cup B)

Considering the values we have for this problem

P(A \cap B) = P(A) + P(B) - P(A \cup B) = 0.8 + 0.75 - 0.95 = 0.6

3000 of them were passed both subjects how many students appeared in the examination?

3000 is 60% of the total t. So

0.6t = 3000

t = \frac{3000}{0.6}

t = 5000

5000 students appeared in the examination.

4 0
3 years ago
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