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spin [16.1K]
3 years ago
11

What mass error (in mg, round to the nearest tenth) would occur in the weighing of 450 mg of a drug if the uncalibrated balance

created a 15 % error in all measurements?
Mathematics
1 answer:
Lubov Fominskaja [6]3 years ago
4 0

Answer: 67.5

Step-by-step explanation:

Given: The mass of drug =  450 mg

The mass percent error = 15%

Which can be written as 0.15.

We use the formula :-

\text{Error}=\text{Previous value }\times\text{Percent error}

Similarly, \text{Mass Error}=\text{Mass of drug }\times\text{Mass percent error}

\Rightarrow\ \text{Mass Error}=450\times0.15=67.5\ mg

Hence, the mass error would be  67.5 mg.

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