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allsm [11]
3 years ago
15

Simplify (2+3x)(7-x)

Mathematics
1 answer:
mariarad [96]3 years ago
7 0

Answer:

3x^2 + 19x + 14

Step-by-step explanation:

(2+3x)(7-x)

14-2x+21x-3x^2

3x^2 + 19x + 14

[cannot be simplified past this point]

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Which of the lines shown is a reasonable trend line for the scatter plot?
Nezavi [6.7K]

Answer:

blue

Step-by-step explanation:

it is going along with the points. we know it cant be red because that line is negative and the dots are going in a positive direction. we know it cant be pink bc it's not even going in the same direction as the points. so it has to be blue

4 0
3 years ago
What is the answer to <br> 11/x - 6/x
EleoNora [17]

Answer:

5/x

Step-by-step explanation:

11-6/x=5/x

6 0
3 years ago
In a MBS first year class, there are three sections each including 20 students. In the first section, there are 10 boys and 10 g
KIM [24]

Answer:

3.52 \times 10^{-9} = 3.52 \times 10^{-7}\% probability that all the 15 students selected are girls

Step-by-step explanation:

The selection is from a sample without replacement, so we use the hypergeometric distribution to solve this question.

Hypergeometric distribution:

The probability of x sucesses is given by the following formula:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

In which:

x is the number of sucesses.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

All girls from the first group:

20 students, so N = 20

10 girls, so k = 10

5 students will be selected, so n = 5

We want all of them to be girls, so we find P(X = 5).

P_1 = P(X = 5) = h(5,20,5,10) = \frac{C_{10,5}*C_{10,5}}{C_{20,5}} = 0.0163

All girls from the second group:

20 students, so N = 20

5 girls, so k = 5

5 students will be selected, so n = 5

We want all of them to be girls, so we find P(X = 5).

P_2 = P(X = 5) = h(5,20,5,5) = \frac{C_{5,5}*C_{15,5}}{C_{20,5}} = 0.00006

All girls from the third group:

20 students, so N = 20

8 girls, so k = 8

5 students will be selected, so n = 5

We want all of them to be girls, so we find P(X = 5).

P_3 = P(X = 5) = h(5,20,5,8) = \frac{C_{8,5}*C_{12,5}}{C_{20,5}} = 0.0036

All 15 students are girls:

Groups are independent, so we multiply the probabilities:

P = P_1*P_2*P_3 = 0.0163*0.00006*0.0036 = 3.52 \times 10^{-9}

3.52 \times 10^{-9} = 3.52 \times 10^{-7}\% probability that all the 15 students selected are girls

7 0
3 years ago
Cedric and Insha solved the same equation using the calculations below.
Mariulka [41]

The first working out is correct, z = 3

3 0
3 years ago
4 pts
3241004551 [841]

Check the picture below.

8 0
3 years ago
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