The area of the sector is 86.81π mm²
<u>Explanation:</u>
Given:
Radius of the sector, 25mm
Angle, α = 50°
Area of the sector, A = ?
We know:
Area of the sector =
On substituting the value, we get:
Therefore, the area of the sector is 86.81π mm²
Solution :
To claim to be tested is whether "the mean salary is higher than 48,734".
i.e. μ > 48,734
Therefore the null and the alternative hypothesis are
and
Here, n = 50
s = 3600
We take , α = 0.05
The test statistics t is given by
t = 2.15
Now the ">" sign in the sign indicates that the right tailed test
Now degree of freedom, df = n - 1
= 50 - 1
= 49
Therefore, the p value = 0.02
The observed p value is less than α = 0.05, therefore we reject . Hence the mean salary that the accounting graduates are offered from the university is more than the average salary of 48,734 dollar.
(q - 3/4)(q + 1/4)
First - q x q = q^2 ( q squared)
Outer - q x 1/4 = 1/4q
Inner - 3/4 x q = - 3/4q
Last - -3/4 x 1/4 = - 3/16
Add all in that order, combine like terms if necessary.
q^2 - 2/4q - 3/16
The missing number would be 100.
e.g 400/2= 200
200/2= 100
100/2 = 50
50/2 = 25
Answer:
100 meters per minute
Step-by-step explanation:
Find his average speed by dividing the distance he walked by the number of minutes it took him:
500/5
= 100
So, his average speed was 100 meters per minute