558 divided by 23 equals
24 with a remainder of 6
The maximum weight that could be held would be 32 pounds. or six five pound weights taking up 18 inches of space, and weighing 30 Lbs, and two one pound weights adding another two inches. You could achieve a greater weight if you had a weight of one-half inch, in which case you could take six 5 lb weights and 1 two pound weight, then you could add a half inch weight bringing the weight to over 32 inches. Since we don't have a half inch weight we can't raise the weight above 32lbs.
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Answer:22/
9
= 2 4/
9
≅ 2.4444444
Step-by-step explanation:
Add: -19 + 9 = -10
Absolute value: abs(the result of step No. 1) = abs(-10) = 10
Divide: the result of step No. 2 / 3 = 10 / 3 = 3.3333333333333 = 10/
3
Subtract: 14 - 22 = -8
Absolute value: abs(the result of step No. 4) = abs(-8) = 8
Divide: the result of step No. 5 / 9 = 8 / 9 = 0.88888888888889 = 8/
9
Subtract: the result of step No. 3 - the result of step No. 6 = 10/
3
- 8/
9
= 10 · 3/
3 · 3
- 8/
9
= 30/
9
- 8/
9
= 30 - 8/
9
= 22/
9
