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3 years ago

Solve to find side C please

Mathematics

1 answer:

Alex73 [517]3 years ago

6 0

Answer:

c= 18.4

Step-by-step explanation:

Since this is a right triangle, we can use trig functions

cos theta = adj/ hyp

cos theta = a/c

cos 57 = 10/c

Multiply each side by c

c cos 57 =10

Divide each side by cos 57

c = 10/cos 57

c=18.36078459

Rounding to the nearest tenth

c= 18.4

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Factor Please help me I will mark as brainliest

aalyn [17]

Answer:

hope this will help you

Step-by-step explanation:

$b { }^{2} - 81 = 0 \\ b {}^{2} = 81 \\ b = \sqrt{81} \\ b = 9$

6 0

3 years ago

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Helpppppppppp assssaaaap

ikadub [295]

<h3>Answer: 250</h3>

==================================================

Explanation:

x = speed of the plane in mph

x-180 = speed of the car, since its 180 mph slower than the plane

For the plane, we can form the equation

distance = rate*time

d = r*t

500 = xt

t = 500/x

For the car, we can say,

d = rt

140 = (x-180)t

140 = (x-180)*(500/x)

140x = 500(x-180)

140x = 500x - 90,000

140x - 500x = -90,000

-360x = -90,000

x = (-90,000)/(-360)

x = 250

The speed of the plane is 250 mph

-----------------------------

Extra info:

The car's speed is x-180 = 250-180 = 70 mph

It takes the plane t = d/r = 500/250 = 2 hours and it takes the car t = d/r = 140/70 = 2 hours. Both vehicles travel for 2 hours, which helps to confirm the answer.

6 0

3 years ago

X + y = 152, 8.5x + 12y = 1,656 How many hats were sold?

Elodia [21]

Answer:

x = 48 and y = 104

Step-by-step explanation:

Given equations are:

$x+y = 152\\8.5x+12y=1656$

From equation 1:

$x = 152-y$

Putting the value of y in equation 2

$8.5(152-y)+12y = 1656\\1292-8.5y+12y = 1656\\3.5y+1292 = 1656\\3.5y = 1656-1292\\3.5y = 364\\\frac{3.5y}{3.5} = \frac{364}{3.5}\\y = 104$

Now we have to put the value of y in one of the equation to find the value of x

Putting y = 104 in the first equation

$x+y = 152\\x+ 104 = 152\\x = 152-104\\x = 48$

Hence,

The solution of the system of equations is x = 48 and y = 104

The value of variable which was assumed for number of hats, is the total number of hats.

6 0

3 years ago

The goals against average (A) for a professional hockey goalie is determined using the formula A=60(g/2). In the formula, g repr

maks197457 [2]

Answer:

g = At/60

Step-by-step explanation:

Given:

A = 60(g/t)

60(g/2) is a mistake in the question which the question has corrected in the comments)

A is the average for a professional hockey goalie.

g is the number of goals scored against the goalie.

t represents the time played in minutes.

Finding 'g':

A = 60(g/t)

can be written as A = (60*g)/t

Multiplying by 't' on both sides:

At = (60*g)*t/t

At = 60*g

Dividing by '60' on both sides:

At/60 = 60*g/60

At/60 = g

⇒ g = At/60

3 0

3 years ago

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If a coin is tossed three times, find probability of getting

Assoli18 [71]

${\large{\textsf{\textbf{\underline{\underline{Given :}}}}}}$

‣ A coin is tossed three times.

${\large{\textsf{\textbf{\underline{\underline{To \: Find :}}}}}}$

‣ The probability of getting,

1) Exactly 3 tails

2) At most 2 heads

3) At least 2 tails

4) Exactly 2 heads

5) Exactly 3 heads

${\large{\textsf{\textbf{\underline{\underline{Using \: Formula :}}}}}}$

$\star \: \tt P(E)= {\underline{\boxed{\sf{\red{ \dfrac{ Favourable \: outcomes }{Total \: outcomes} }}}}}$

${\large{\textsf{\textbf{\underline{\underline{Solution :}}}}}}$

★ When three coins are tossed,

then the sample space = {HHH, HHT, THH, TTH, HTH, HTT, THT, TTT}

[here H denotes head and T denotes tail]

⇒Total number of outcomes $\tt [ \: n(s) \: ]$ = 8

1) Exactly 3 tails 

Here

• Favourable outcomes = {HHH} = 1

• Total outcomes = 8

$\therefore \sf Probability_{(exactly \: 3 \: tails)} = \red{ \dfrac{1}{8}}$

2) At most 2 heads

[It means there can be two or one or no heads]

Here

• Favourable outcomes = {HHT, THH, HTH, TTH, HTT, THT, TTT} = 7

• Total outcomes = 8

$\therefore \sf Probability_{(at \: most \: 2 \: heads)} = \green{ \dfrac{7}{8}}$

3) At least 2 tails 

[It means there can be two or more tails]

Here

• Favourable outcomes = {TTH, TTT, HTT, THT} = 4

• Total outcomes = 8

$\longrightarrow \sf Probability_{(at \: least \: 2 \: tails)} = \dfrac{4}{8}$

$\therefore \sf Probability_{(at \: least \: 2 \: tails)} = \orange{\dfrac{1}{2}}$

4) Exactly 2 heads 

Here

• Favourable outcomes = {HTH, THH, HHT } = 3

• Total outcomes = 8

$\therefore \sf Probability_{(exactly \: 2 \: heads)} = \pink{ \dfrac{3}{8}}$

5) Exactly 3 heads

Here

• Favourable outcomes = {HHH} = 1

• Total outcomes = 8

$\therefore \sf Probability_{(exactly \: 3 \: heads)} = \purple{ \dfrac{1}{8}}$

$\rule{280pt}{2pt}$

8 0

2 years ago