The slopes of perpendicular lines are negative reciprocals.The slope of the given line is 4.The slope of the perpendicular is -1/4.
Now we need to find the equation of a line that has slope -1/4 and passes through the point (4, 20).
We use the point-slope form of the equation of a line, where m = slope, and the point is (x1, y1).
y - y1 = m(x - x1)
y - 20 = -1/4(x - 4)
-4y + 80 = x - 4
x + 4y = 84
X-4y=-2
-x. -x
4y=-2-x
4y=x-(-2)
/4. /4
Y=4x+2/4
3x-y=5
-3x. -3x
-y=5-3x
-y=-3x+5
/-1. /-1
Y=3x-5
Answer:
2
Step-by-step explanation:
In short, for a vertical parabola, namely one whose independent variable is on the x-axis, usually is x², if the leading term coefficient is negative, the parabola opens downward, and its peak or vertex is at a maximum, check the picture below at the left-hand-side.
and when the leading term coefficient is positive, the parabola opens upwards, with a minimum, check the picture below at the right-hand-side.
Answer:
The GCF is 2
Step-by-step explanation:
Here, we want to find the greatest common factors of the two terms
We have the terms written in terms of the products of their multiples as follows;
4c^3 = 2 * 2 * c * c* c
6m^2 = 2 * 3 * m * m
As we can see, the greatest common factor of the two is simple the value 2