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damaskus [11]
3 years ago
9

How to solve for x?

Mathematics
2 answers:
klemol [59]3 years ago
8 0
So 128 and the angle right next to it which is inside the triangle and supplementary angles, meaning that they both add up to 180. so you can do 180 - 128 is 52. so then 52 and 47 are both inside the triangle and so is x. add both 52 and 47 and then subtract it by 180 to find x. 
x is 81
hope this helps!
Viktor [21]3 years ago
5 0
Multiply both sides by x so that x will be in the numerator
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How do you work out this problem?<br><br>3x+15=66
vivado [14]

3x + 15 = 66

<u>      -15    -15</u>

3x =  51

Divide 51 by 3 which equals 17.

4 0
4 years ago
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Can someone help me I'm doing my packet and the quest is hard
CaHeK987 [17]
The answer would be y=-3/4x-3
5 0
2 years ago
Translate to an algebraic statement.<br> "The quotient of twice a number and 7 is 20."
Genrish500 [490]

<u>Answer:</u>

  • Translation: 2x/7 = 20

<u>Step-by-step explanation:</u>

  • <em>When we listen to the word "quotient", it means the solution to a division problem. </em>
  • <em>An unknown number that has been multiplied by 2 is in the numerator because it came before the 7 in the statement. </em>
  • <em>The number "7" is in the denominator because it came after the 2x in the statement. </em>
  • <em>The word "is" represents an equal sign.</em>
  • <em>The solution to the division problem (quotient) is 20. </em>

<u><em>If we put these clues together, we get 2x/7 = 20 as our translated equation.</em></u>

<u>Hence, our algebraic statement is 2x/7 = 20. The key is to listen to the statement. </u>

BrainiacUser1357

4 0
3 years ago
A local gym instructor has a course load that allows her to teach eight classes. At an interest meeting, 8 people wanted high-­‐
cricket20 [7]

Answer:

<u>The final curse load of the local gym instructor is this:</u>

<u>High-­‐impact aerobics = 1</u>

<u>Low-­‐impact aerobics =  4</u>

<u>Jazzercise = 1</u>

<u>Step exercise = 2</u>

Step-by-step explanation:

1. Let's apportion the class load using the Hamilton method

Number of classes the local gym instructor can teach = 8

Total number of students that want to take a class = 114 (8 people wanted high-­‐impact aerobics, 64 wanted low-­‐impact aerobics, 11 wanted jazzercise, and 31 wanted step exercise)

Standard divisor = 114/8 = 14.25

Now, we can apportion the students in in Standard quotas, this way:

High-­‐impact aerobics = 8/14.25 = 0.5614

Low-­‐impact aerobics = 64/14.25 = 4.49

Jazzercise = 11/14.25 = 0.7719

Step exercise = 31/14.25 = 2.1754

Now, we find the Minimum quota, just considering the whole number and don't taking into account the decimals, this way:

High-­‐impact aerobics = 0

Low-­‐impact aerobics =  4

Jazzercise = 0

Step exercise = 2

As we can see we have 6 classes and there are 2 still pending. Those 2 goes to the classes with the highest decimal portion, in this case, Jazzercise .7719 and High-­‐impact aerobics with .5614.

<u>The final course load is this:</u>

<u>High-­‐impact aerobics = 1</u>

<u>Low-­‐impact aerobics =  4</u>

<u>Jazzercise = 1</u>

<u>Step exercise = 2</u>

7 0
3 years ago
The price of a gym membership has a one-time sign-up fee and a monthly fee. The price can be modeled by the function y = 10x + 1
monitta
15; it represents the one-time sign-up fee

The y-intercept can be found either on the graph where the line intercepts the y-axis, or b in the equation y=mx+b.

It represents the fee because it will be charged even if the number of months (x) is zero. 10 is the monthly fee because it is multiplied by x, the number of months.
8 0
3 years ago
Read 2 more answers
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