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ohaa [14]
3 years ago
5

X(x+7)=0 solve whatever this id

Mathematics
1 answer:
Anit [1.1K]3 years ago
5 0

Step-by-step explanation:

x(x + 7) = 0

By Zero Product rule,

either x = 0 or (x + 7) = 0.

=> x = 0 or x = -7.

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Complete the following sentence<br><br> If x is to 6 as 10 is to 15, then x is equal to .
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Answer:

x=4

Step-by-step explanation:

x/6 = 10/15

x/6 = 2/3

3x=12

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Which equation represents the function on the graph?
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Answer:

A. Sin 2x

Step-by-step explanation:

This is a trig function and has the shape of sine or cosine. Since it intersects at (0,0), it is likely a sine graph. A normal sine graph starts at (0,0), crests up at 1, and crosses back down at the x-axis at (3.14, 0). However, this graph starts at (0,0) and crosses back again at half that value. This graph has been horizontally compressed by multiplication of a number greater than 1. So this graph is Sin 2x.

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Leave your answers as a fraction or improper fraction.
storchak [24]

Answer:

Soda tax — Should people have to pay an extra tax on soda or junk food?

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A total of at least five entries for each side (10 entries total—two to three sentences each)

Accurate facts used to support both perspectives

At least two properly cited sources used for research

Step-by-step explanation:

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0.425 as a fraction in simplest form
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add the term that makes the given expression into a perfect square. write the result as the square of a bracketed expression c s
Molodets [167]
<h2>Perfect Squares</h2>

Perfect square formula/rules:

  • a^2+2ab+b^2=(a+b)^2
  • a^2-2ab+b^2=(a-b)^2

Trinomials are often organized like ax^2+bx+c.

The <em>b</em> value in this case is <em>c</em>, and it will always equal the square of half of the <em>b</em> value.

  • Perfect square trinomial: ax^2+bx+(\dfrac{b}{2})^2
  • or ax^2-bx+(\dfrac{b}{2})^2

<h2>Solving the Question</h2>

We're given:

  • c^2-4c

In a trinomial, we're given the ax^2 and bx values. <em>a</em> in this case is 1 and <em>b</em> in this case is 4. To find the third value by dividing 4 by 2 and squaring the quotient:

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Therefore, the term that we can add is + 4.

c^2-4c+4

To write this as the square of a bracketed expression, we can follow the rule a^2-2ab+b^2=(a-b)^2:

(c-2)^2

<h2>Answer</h2>

c^2-4c+4

(c-2)^2

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