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julsineya [31]
3 years ago
11

The expression 937(1+x) gives the markup price of a computer, where x is the percent of the markup written in decimal form. Whic

h part of the expression represents the percent, in decimal form, of the initial price that is being paid? Enter your answer in
The expression 0.08x+(x−200) models the final price of a computer with an instant rebate in a state that charges a sales tax.

Enter the expression in the box that represents the amount of tax that is paid on the computer.
Mathematics
1 answer:
jarptica [38.1K]3 years ago
6 0
The expression is 203.422+ X
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Taisha works a part-time job while taking evening classes at her local community at her local community college. She sets up a p
Mrrafil [7]

Step-by-step explanation:

Taisha is losing money. Exactly how much can be found in this equation.

12 months in a year so that's our coefficient.

292.36(12)   -     320.67(12)=−339.72

(pay per month)   (school fee per month)

She is 339.72 dollars in debt.

7 0
3 years ago
There are 25 students performing in the holiday concert. Of the students, 11 are boys.
tia_tia [17]

Answer:

0.44 (44%) of the students are boys.

Step-by-step explanation:

Hope this helps!

✧◝(⁰▿⁰)◜✧

3 0
2 years ago
Mai had 5 candy bars. She ate half of one candy bar and decided to distribute the remaining bars between her two sisters and her
brilliants [131]
1 and 2/3 is the answer
7 0
3 years ago
Read 2 more answers
Consider the region bounded by the curves y=|x^2+x-12|,x=-5,and x=5 and the x-axis
Tasya [4]
Ooh, fun

what I would do is to make it a piecewise function where the absolute value becomse 0

because if you graphed y=x^2+x-12, some part of the garph would be under the line
with y=|x^2+x-12|, that part under the line is flipped up

so we need to find that flipping point which is at y=0
solve x^2+x-12=0
(x-3)(x+4)=0
at x=-4 and x=3 are the flipping points

we have 2 functions, the regular and flipped one
the regular, we will call f(x), it is f(x)=x^2+x-12
the flipped one, we call g(x), it is g(x)=-(x^2+x-12) or -x^2-x+12
so we do the integeral of f(x) from x=5 to x=-4, plus the integral of g(x) from x=-4 to x=3, plus the integral of f(x) from x=3 to x=5


A.
\int\limits^{-5}_{-4} {x^2+x-12} \, dx + \int\limits^{-4}_3 {-x^2-x+12} \, dx + \int\limits^3_5 {x^2+x-12} \, dx

B.
sepearte the integrals
\int\limits^{-5}_{-4} {x^2+x-12} \, dx = [\frac{x^3}{3}+\frac{x^2}{2}-12x]^{-5}_{-4}=(\frac{-125}{3}+\frac{25}{2}+60)-(\frac{64}{3}+8+48)=\frac{23}{6}

next one
\int\limits^{-4}_3 {-x^2-x+12} \, dx=-1[\frac{x^3}{3}+\frac{x^2}{2}-12x]^{-4}_{3}=-1((-64/3)+8+48)-(9+(9/2)-36))=\frac{343}{6}

the last one you can do yourself, it is \frac{50}{3}
the sum is \frac{23}{6}+\frac{343}{6}+\frac{50}{3}=\frac{233}{3}


so the area under the curve is \frac{233}{3}
6 0
3 years ago
It's always a good idea to check your solutions to any equation in the original equation. When solving an absolute value equatio
Andru [333]

You should must check for an extraneous solution when  the variable appears both inside and outside the absolute value expression

<h3>What is an extraneous solution?</h3>

An extraneous solution is a solution that in obtained after completely solving an equation but it does not  work in the original given equation.

You should must check for an extraneous solution when  the variable appears both inside and outside the absolute value expression (Option D).

Learn more about extraneous solution: brainly.com/question/14054707

#SPJ1

7 0
2 years ago
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