Answer:
Step 1: Simplify both sides of the equation.
6(3x−5)−7x=25
(6)(3x)+(6)(−5)+−7x=25(Distribute)
18x+−30+−7x=25
(18x+−7x)+(−30)=25(Combine Like Terms)
11x+−30=25
11x−30=25
Step 2: Add 30 to both sides.
11x−30+30=25+30
11x=55
Step 3: Divide both sides by 11.
x=5
Step-by-step explanation:
<h3>Given</h3>
A(-3, 1), B(4, 5)
<h3>Find</h3>
coordinates of P on AB such that AP/PB = 5/2
<h3>Solution</h3>
AP/PB = 5/2 . . . . . desired result
2AP = 5PB . . . . . . multiply by 2PB
2(P-A) = 5(B-P) . . . meaning of the above
2P -2A = 5B -5P . . eliminate parentheses
7P = 2A +5B . . . . . collect P terms
P = (2A +5B)/7 . . . .divide by the coefficient of P
P = (2(-3, 1) +5(4, 5))/7 . . . . substitute the given points
P = (-6+20, 2+25)/7 . . . . . . simplify
P = (2, 3 6/7)
Answer:
I'm pretty sure the answer is A) Dilation.
Answer: v = 2
Step-by-step explanation:
Your equation:
You can multiply both sides by 8 to eliminate the fraction, which gives you this:
6v - 5 = 7
Then, you can solve for it:
6v = 12
v = 2
Answer:
The particle will travel 6 feet in first 2 seconds.
Step-by-step explanation:
We have been given that a particle moves according to the velocity equation 
. We are asked to find the distance that the particle will travel in its first 2 seconds.
Now, we will eliminate the absolute value sign as:
![s(t)=[\frac{6t^3}{3}-\frac{18t^2}{2}+12t]^1_0 +[\frac{-6t^3}{3}+\frac{18t^2}{2}-12t]^2_1](https://tex.z-dn.net/?f=s%28t%29%3D%5B%5Cfrac%7B6t%5E3%7D%7B3%7D-%5Cfrac%7B18t%5E2%7D%7B2%7D%2B12t%5D%5E1_0%20%2B%5B%5Cfrac%7B-6t%5E3%7D%7B3%7D%2B%5Cfrac%7B18t%5E2%7D%7B2%7D-12t%5D%5E2_1)
![s(t)=[2t^3-9t^2+12t]^1_0 +[-2t^3+9t^2-12t]^2_1](https://tex.z-dn.net/?f=s%28t%29%3D%5B2t%5E3-9t%5E2%2B12t%5D%5E1_0%20%2B%5B-2t%5E3%2B9t%5E2-12t%5D%5E2_1)
Therefore, the particle will travel 6 feet in first 2 seconds.
