All categories

3 years ago

Given the conditional statement c→~b, which of the following is the converse

Mathematics

1 answer:

exis [7]3 years ago

3 0

Answer:

To form the converse of the conditional statement, interchange the hypothesis and the conclusion. The converse of "If it rains, then they cancel school" is "If they cancel school, then it rains." To form the inverse of the conditional statement, take the negation of both the hypothesis and the conclusion.

Step-by-step explanation:

You might be interested in

Mrs. Williams needed to make 4 1/2 of fruit salad for a class party.

ziro4ka [17]

Answer:

strawberry=7/8

Step-by-step explanation:

treat strawberry as x

add on proportions

1 1/8+ 3/4+ 1 3/4 + x = 4 1/2

(9+6+14)/8 + x = 9/2

29/8 +x = 9/2

x= 9/2 - 29/8

x= (36-29)/8

x=7/8

3 0

3 years ago

A red kangaroo can cover 40 feet in 1 jump.How Many feet can the red kangaroo cover in 12 jumps

Nikitich [7]

480 feet in 12 jumps
40 times 12

4 0

3 years ago

Read 2 more answers

Graph this solution x < 4

morpeh [17]

Answer:

see below

Step-by-step explanation:

x < 4

x is less than 4

Since it is less than, there is an open circle at 4

less than means the line goes to the left

5 0

2 years ago

Evaluate the limit as x approaches 0 of (1 - x^(sin(x)))/(x*log(x))

e-lub [12.9K]

$sin~ x \approx x ~ ~\sf{as}~~ x \rightarrow 0$

We can replace sin x with x anywhere in the limit as long as x approaches 0.

Also,

$\large \lim_{ x \to 0 } ~ x^x = 1$

I will make the assumption that log(x)=ln(x).

The limit result can be proven if the base of log(x) is 10.

$\large \lim_{x \to 0^{+}} \frac{1- x^{\sin x} }{x \log x } \\~\\ \large = \lim_{x \to 0^{+}} \frac{1- x^{\sin x} }{ \log( x^x) } \\~\\ \large = \lim_{x \to 0^{+}} \frac{1- x^{x} }{ \log( x^x) } ~~ \normalsize{\text{ substituting x for sin x } } \\~\\ \large = \frac{\lim_{x \to 0^{+}} (1) - \lim_{x \to 0^{+}} \left( x^{x}\right) }{ \log( \lim_{x \to 0^{+}}x^x) } = \frac{1-1}{\log(1)} = \frac{0}{0}$

We get the indeterminate form 0/0, so we have to use Lhopitals rule

 $\large \lim_{x \to 0^{+}} \frac{1- x^{x} }{ \log( x^x) } =_{LH} \lim_{x \to 0^{+}} \frac{0 -x^x( 1 + \log (x)) }{1 + \log (x) } \\ = \large \lim_{x \to 0^{+}} (-x^x) = \large - \lim_{x \to 0^{+}} (x^x) = -1$

Therefore,

 $\large \lim_{x \to 0^{+}} \frac{1- x^{\sin x} }{x \log x } =\boxed{ -1}$

3 0

2 years ago

2- En una habitación cuadrada de 4 m de lado se coloca una alfombra circular de 3 m de diámetro. ¿Cuál es la superficie cubierta

dezoksy [38]

Answer:

7.065 m ^ 2

8.935 m ^ 2

Step-by-step explanation:

The first thing is to calculate the surface of each one, that is, the area

For the room that is square, each side measures 4m, therefore:

As = 4 * 4 = 16 m ^ 2

The area of the carpet is that of a circle, that its area is the number pi times the radius squared, we know that the radius is half the diameter, therefore r = 3/2 = 1.5 m

replacing in the area formula

Ac = pi * r ^ 2 = 3.14 * 1.5 ^ 2

Ac = 7.065 m ^ 2

In other words, the area covered by the carpet is 7,065 m ^ 2 and the area not covered would be the subtraction between the area of the room minus the area of the carpet, that is:

16 m ^ 2 - 7.065 m ^ 2 = 8.935 m ^ 2

8.935 m ^ 2 would be the area that the carpet does not subside.

7 0

3 years ago