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3 years ago

Which pair of properties apply to both sound and electromagnetic waves?

Physics

2 answers:

exis [7]3 years ago

5 0

The answer would be A because sound waves and electomagnetic waves carry energy and they can both refract.

Elena L [17]3 years ago

3 0

Answer: A. Both waves carry energy and refract.

Explanation: Rarefaction is where vibrating particles are spread apart.

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Suppose you're on a hot air balloon ride, carrying a buzzer that emits a sound of frequency f. If you accidentally drop the buzz

amid [387]

Answer:

Explanation:

The Doppler effect describes the change in frequency or wavelength of a wave in relation to an observer who is moving relative to the wave source, or the wave source is moving relative to the observer, or both.

if the observer and the source move away from each other as is the case for this problem, the wavelength heard by the observer is bigger.

The frequency is the inverse from the wavelength, so the frequency heard will increase.

The sound intensity depends inversely on the area in which the sound propagates. When the buzzer is close, the area is from a small sphere, but as the buzzer moves further away, the wave area will be from a larger sphere and therefore the intensity will decrease.

7 0

4 years ago

28. Calculate the weight of a 1,789 kg car on the Earth.

skad [1K]

Answer:

From the equation ΣF = ma, one can say that the mass is 1800 kg, and the acceleration of gravity is -9.8 meters. Multiply those together and it is -17640 newtons.

Explanation:

plz send a brainleast

3 0

3 years ago

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Alborosie

Interesting question :)

8 0

4 years ago

Before hanging new William Morris wallpaper in her bedroom, Brenda sanded the walls lightly to smooth out some irregularities on

Allushta [10]

To solve the exercise it is necessary to apply the equations necessary to apply Newton's second law and the concept related to frictional force.

An angle of 30 degrees is formed on the vertical at an applied force of 2.3N

In this way the frictional force, opposite to the movement will be given by

$f_k = \mu_k N$

where,

$\mu_k =$ Kinetic friction constant

N = Normal Force (Mass*gravity)

The friction force is completely vertical and opposes the rising force of 2.3 N. The Normal force acts perpendicular to the surface (vertical) therefore corresponds to the horizontal component of the applied force.

The ascending force would be given by

$F_v = 2.3N*Cos30 = 1.99N$

As the block is moving upward, the friction force acts downward, also its weight acts downward. We can have

$2.3N+f_k = 1.99N$

$f_k = 0.31N$

Considering the horizontal force the normal force on the block must be balanced by the horizontal component of pishing foce

$N = 2.3sin30$

$N = 1.15N$

Then the frictional force

$f_k = \mu_k N$

$0.31N = \mu_k 1.15$

$\mu_k = \frac{0.31}{1.15}$

$\mu_k =0.26$

Therefore the coefficient of kinetic friction is 0.26

3 0

3 years ago

Edward travels 150 kilometers due west and then 200 kilometers in a direction 60° north of west. What is his displacement in the

lions [1.4K]

We must decompose the displacement vector to find the new displacement to the west.

$d_{x}=v.cos\O \\ d_{x}=200. \frac{1}{2} \\ d_{x}=100km$

Adding all displacements to West, It comes:

$\Delta S= d_{o}+d_{x} \\ \Delta S= 150+100 \\ \boxed {\Delta S= 250 km}$

If you notice any mistake in English, please let me know, because I'm not native.

8 0

3 years ago