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3 years ago

What are some real-world examples that illustrate the relationship between kinetic energy and potential energy?

1 answer:

7 0

Potential energy is energy that is stored in an object. As the rubber band is released, potential energy is changed to motion. Kinetic energy is energy of motion. A rubber band flying through the air has kinetic energy.

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Controlling the amount of current in a circuit by opposing the flow of charge

Vera_Pavlovna [14]

Answer:

Resistor

Explanation:

Resistor provides resistance to the flow of electric current in a circuit.

It controls the amount of current in a circuit by acting as a barrier to the flow of electric charges

8 0

3 years ago

Read 2 more answers

Select the object that has the most gravitational force. a sand grain a marble a bowling ball a tennis ball

Anna35 [415]

So we want to know which object has a gravitational force of the greatest magnitude. Since gravitational force depends on the mass of the object, the object with the greatest mass will have the greatest magnitude of the gravitational force. In this case that is the bowling ball.

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3 years ago

Read 2 more answers

A cart traveling at 0.3 m/s collides with stationary object. After the collision, the cart rebounds in the opposite direction. T

padilas [110]

Answer:

Explanation:

First case

A cart speed is 0.3m/s. i.e the initial velocity is u=0.3m/s

It collide with a stationary body, then after collision the ball rebounds and move in opposite direction. This shows that the ball have a velocity after impulse let say v

Then, impulse is given as the change in linear momentum of a body

Impulse =m∆v

I=m(v-u)

Note, momentum is a vector quantity.

I=m(v--u)

I=m(v+u)

I=m(v+0.3)

I¹=0.3m+mv. Equation 1

Second case

A cart speed is 0.3m/s. i.e the initial velocity is u=0.3m/s

It collide with a stationary body, then after collision the ball is at rest, this show that the final velocity is v=0

Then, impulse is given as the change in linear momentum of a body

Impulse =m∆v

I=m(v-u)

Note, momentum is a vector quantity.

I=m(v--u)

I=m(v+u)

In this case v=0 u=0.3m/s

I=m(0+0.3)

I²=0.3m. Equation 2

If we compare impulse 1 (I¹) to impulse 2 (I²)

Subtract equation 2 from 1

We have, I¹ - I² =0.3m+mv -0.3m

I¹ - I² =mv

I¹ =mv+I²

We notice that the first impulse (I¹) is greater than second impulse (I²) by mv.

The correct answer is A

5 0

3 years ago

Morse code and string phone cup

polet [3.4K]

Answer:

Following are the responses to the given question:

Explanation:

Following are the difference in the speed and accuracy:

The biggest difference was its tone between both the cup method as well as the Morse code. One should talk using cup system and sequence system and let its covering be understood in Morse code, just a series of beeps weren’t tangible... Secondly, a method of cup involves a range string. Rukun Negara is often distributed by cable, but this is a greater range. It reaches concurrently in those other areas.

In the case of using the string method for the block, its distance and stiffness of the string are limited and the barriers are eliminated. It will certainly be convenient and clearer if one utilizes Sign language.

If two experts are acting like such a machine on both sides, their information between both the 2 persons is smoother and quicker as they will not have to wait for data from a third person which may create another pause at the time.

Morse code is faster, eventually. For some very small periods when sensitive information is not transmitted, strings or cup methods must be reserved.

8 0

3 years ago

A 0.05-m3 rigid tank initially contains refrigerant-134a at 0.8 MPa and 100 percent quality. The tank is connected by a valve to

lesya692 [45]

Answer:

A= 203 KJ

B= 54 Kg

Explanation:

The initial specific volumes and internal energies are obtained from A-12 for a given pressure and state. The enthalpy of the refrigerant in the supply line is determined using the saturated liquid approximation for the given temperature with data from A-11. The mass that has entered the tank is:

Δm = m₂ – m₁

= V(1/α₂ – 1/α₁)

= 0.05 (1/0.0008935 – 1/ 0.025645)Kg

= 54Kg

The heat transfer is obtained from the energy balance:

ΔU= $m_i_n$ $h_i_n$ + $Q_n_e_t$

m₂u₂ – m₁u₂ = $m_i_n$ $h_i_n$ + $Q_n_e_t$

$Q_n_e_t$ = m₂u₂ – m₁u₁ – $m_i_n$

= V/α₂u₂ - V/α₁u₁ – $m_i_n$

=(0.05/0.0008935 . 116.72 – 0.05/0.025645 . 246.82 – 54.108.28) Kj

= 203 KJ

8 0

3 years ago