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ycow [4]
2 years ago
12

Edward travels 150 kilometers due west and then 200 kilometers in a direction 60° north of west. What is his displacement in the

westerly direction?
Physics
1 answer:
lions [1.4K]2 years ago
8 0
     We must decompose the displacement vector to find the new displacement to the west.

d_{x}=v.cos\O \\ d_{x}=200. \frac{1}{2}  \\ d_{x}=100km
  
     Adding all displacements to West, It comes:

\Delta S= d_{o}+d_{x} \\ \Delta S= 150+100 \\ \boxed {\Delta S= 250 km}

If you notice any mistake in English, please let me know, because I'm not native.

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The experimental apparatus shown in the figure above contains a pendulum consisting of a 0.66 kg ball attached to a string of le
lara31 [8.8K]

The problem is solved and the questions are answered below.

Explanation:

a. To calculate the speed of the 0.66 kg ball just before the collision

V₀ + K₀ = V₁ + K₁

= mgh₀ = 1/2 mv₁²

where, h= r - r cosθ

V = \sqrt{2gh}

 V = 2.42 m/s

b. Calculate the speed of the 0.22 kg ball immediately after the collision

y = y₀ + Vy₀t - 1/2 gt²

0 = 1.2 - 1/2 gt²

t = 0.495 s

x = x₀ + Vx₀t

1.4 = 0 + vx₀ (0.495)

Vx₀ = 2.83 m/s

C. To Calculate the speed of the 0.66 kg ball immediately after the collision

m₁ v₁ = m₁ v₃ + m₂ v₄

(0.66)(2.42) = (0.66) v₃ + (0.22)(2.83)

V₃ = 1.48 m/s

D. To Indicate the direction of motion of the 0.66 kg ball immediately after the collision is to the right.

E. To Calculate the height to which the 0.66 kg ball rises after the collision

V₀ + k₀ = V₁ + k₁

1/2 mv₀² = mgh₁

h₁ = v₀²/2 g

  = 0.112 m

F. Based on your data, No the collision is not elastic.

Δk = 1/2 m₁v₃² =1/2 m₂v₄² - 1/2 m₁v₁²

     = 1/2 (0.66)(1.48)² + 1/2 (0.22)(2.83)² - 1/2 (0.66)(2.42)²

    = - 0.329 J

Hence, kinetic energy is not conserved.

8 0
2 years ago
A paper clip that has a mass of 1.5 grams is thrown into the air and initially has a kinetic energy of 0.013 J.
Aleksandr [31]

answer

v = 4.2\frac{m}{s}

set up an equation

we can use the formula for kinetic energy since we know mass and kinetic energy

K = \frac{mv^{2}}{2}

v = \sqrt{\frac{2K}{m} }

values

K = 0.013 J

m = 1.5g = 0.0015 kg

plug in values

v = \sqrt{\frac{2*0.013}{0.0015} }

v = 4.2\frac{m}{s}

3 0
3 years ago
Which atom is invloved in giving your heart energy to beat ?
Juli2301 [7.4K]

Answer:

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Explanation:

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Calculate the pressure exerted by a man having mass 50 kg standing on one feet having area 500cm2​
Burka [1]

Answer:

9800 Pa

Explanation:

Data: pressure-?

Force- mass ×acceleration

= 50× 9.8m/s^2

=490N

Area= 500cm^2=0.05m^2

pressure= force/ area

p=F/A

P= (490N)/( 0.05m^2)

=9800 Pa

7 0
3 years ago
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