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ycow [4]
3 years ago
12

Edward travels 150 kilometers due west and then 200 kilometers in a direction 60° north of west. What is his displacement in the

westerly direction?
Physics
1 answer:
lions [1.4K]3 years ago
8 0
     We must decompose the displacement vector to find the new displacement to the west.

d_{x}=v.cos\O \\ d_{x}=200. \frac{1}{2}  \\ d_{x}=100km
  
     Adding all displacements to West, It comes:

\Delta S= d_{o}+d_{x} \\ \Delta S= 150+100 \\ \boxed {\Delta S= 250 km}

If you notice any mistake in English, please let me know, because I'm not native.

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A 7.45 nC charge is located 1.66 m from a 4.22 nC point charge. (a) Find the magnitude of the electrostatic force that one charg
BaLLatris [955]

Answer:

a.F=1.03\times 10^{-7}N

b.Repulsive

Explanation:

We are given that

q_1=7.45nC=7.45\times 10^{-9}C

1nC=10^{-9}C

q_2=4.22nC=4.22\times 10^{-9}C

r=1.66m

We know that

Electrostatic force =F=k\frac{q_1q_2}{r^2}

r=Distance between q_1\;and\;q_2

k=Constant=9\times 10^9Nm^2C^{-2}

Using the formula

a.The magnitude of the electrostatic force=F=\frac{9\times 10^9\times 7.45\times 10^{-9}\times 4.22\times 10^{-9}}{(1.66)^2}

The magnitude of the electrostatic force=F=1.03\times 10^{-7}N

b.Both charge are positive .We know that when like charges repel each other and unlike charges attract to each other.

Therefore, the force between given charges is repulsive.

7 0
3 years ago
In order to determine the speed of an object, what measurements must be made?
Virty [35]

Answer:

You need to have the distance traveled and the time it took to travel that distance.

Explanation:

5 0
3 years ago
The scientists that was the first to organize the elements into a table was
Murrr4er [49]
The first scientist was Mendeleev
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3 years ago
Can someone explain with the Answers pls?
Dovator [93]

Answer:

a) The frequency of the third harmonic is 786 Hz

b) The frequency of the first harmonic is 340 Hz

c) The frequency of the fifth harmonic is 1640 Hz

Explanation:

The rule is as follows:

If the first harmonic frequency (also called the fundamental frequency) is F, then:

The frequency of the second harmonic (also called the second overtone) is:

2*F

The frequency of the third harmonic (also called the third overtone) is:

3*F

And so on.

With this information, we can answer the questions:

a) We want to find the frequency of the third harmonic, such that the frequency of the first harmonic is 262 Hz.

Then we have F = 262Hz

And the frequency of the third harmonic will be:

3*F = 3*262Hz = 786 Hz

b) First harmonic for a string whose fifth harmonic frequency is 1700Hz.

Let's define F as the first frequency (the one we want to find)

Then the fifth harmonic frequency can be written as:

5*F = 1700Hz

With this equation we can find the value of F:

F = 1700Hz/5 = 340Hz

c) We want to find the fifth harmonic for a string whose third overtone (this is the same as the third harmonic) frequency is 984 Hz.

Then if the frequency of the first harmonic is F, we know that:

3*F = 984 Hz

With this we can find the value of F:

F = 984 Hz/3 =328 Hz

Now that we know the frequency of the first harmonic, we can find the frequency of the fifth harmonic:

5*F = 5*328 Hz = 1640 Hz

8 0
3 years ago
Tarzan, in one tree, sees Jane in another tree. He grabs the end of a vine with length 20m that makes an angle of 45° with the v
nadezda [96]

Answer:

yes

Explanation:

3 0
4 years ago
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