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SpyIntel [72]
3 years ago
14

Given f (x) = 17 minus x squared, what is the average rate of change in f(x) over the interval [1, 5]?

Mathematics
2 answers:
PolarNik [594]3 years ago
8 0

Answer:

The average rate of change of the function over the given interval is -6

Step-by-step explanation:

The function we want to find its average rate of change is;

F(x) = 17 - x^2

Mathematically, the average rate of change of a function F(x) over an interval (a,b) can be calculated as;

{F(b) - F(a)}/(b-a)

According to this question, a = 1 and b = 5

F(a) = F(1) = 17 -(1)^2 = 17 -1 = 16

F(b) = F(5) = 17 - 5^2 = 17-25 = -8

So making the substitution; we have

(-8)-16/(5-1) = -24/4 = -6

Luda [366]3 years ago
8 0

Answer:

A: -6

Step-by-step explanation:

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