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Anit [1.1K]
3 years ago
15

, how is electrostatic force related to amount of charge?

Physics
1 answer:
marusya05 [52]3 years ago
8 0

Answer:Explanation: Electrostatic force is directly related to the charge of each object. So if the charge of one object is doubled, then the force will become two times greater. Two times 0.080 N is 0.160 N.

Explanation:

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these are the types of attractions found between molecules. their strength determines the state of the substance at room tempera
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<h2>Answer</h2>

The physical state of the elements depends upon the <u>attraction forces </u>and their <u>kinetic energy</u>.

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A grating has 2000 slits/cm/cm. How many full spectral orders can be seen (400 to 700 nmnm) when it is illuminated by white ligh
Anton [14]

With the use of the formula SinФ = nλ / d, there are 16 spectral orders which can be seen when it is illuminated by white light.

Given that a grating has 2000 slits/cm. That is,

d = 0.01 / 2000

d = 5 x 10^{-6} m

The wavelength λ = (700 - 400) nm

λ = 300 x 10^{-9} m

To calculate how many full spectral orders that can be seen (400 to 700 nm) when it is illuminated by white light, we will use the below formula

SinФ = nλ / d

Φ = Sin^{-1} (nλ / d)

When n = 1

Φ = Sin^{-1}(300 x 10^{-9}/ 5 x 10^{-6} )

Φ = 3.4 degrees

when n = 2

Φ = Sin^{-1}(2 x 300 x 10^{-9}/ 5 x 10^{-6} )

Ф = 6.9 degrees

When n = 3

Ф = Sin^{-1}(3 x 300 x 10^{-9}/ 5 x 10^{-6} )

When n = 16

Ф = Sin^{-1}(16 x 300 x 10^{-9}/ 5 x 10^{-6} )

Ф = Sin^{-1}(0.96)

Ф = 73.7 degrees

when n = 17

Ф = Sin^{-1}(17 x 300 x 10^{-9}/ 5 x 10^{-6} )

Ф = Sin^{-1}(1.05)

Ф = Error ( that is, it does not exist)

Therefore, there are 16 spectral orders which can be seen when it is illuminated by white light.

Learn more about double slit here: brainly.com/question/4449144

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2 years ago
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Answer:

<h2> Ah Filipino ka rin?</h2>

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<h2>Saya nmen</h2>
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The scientific method is nothing more than a process for discovering answers. While the name refers to “science,” this method of problem solving can be used for any type of problem
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