Ask question

Ask question

All categories

8_murik_8 [283]

3 years ago

10

what is the change in the force of gravity between any two bodies when mass of each body is double keeping the distance between

them constant?

1 answer:

frez [133]3 years ago

8 0

Please find attached photograph for your answer. Do comment if you have any query.. Please do mark me Brainliest if you like my answer

You might be interested in

Which Richter magnitude range can be recorded by instruments but isn't felt? A. less than 2.9 B. 3.0 – 4.9 C. 5.0 – 5.9 D. 6.0 a

algol [13]

A. anything less than 3.0 magnitude on a richters scale usually can't be felt by humans but instruments can pick it up.

3 0

3 years ago

Read 2 more answers

In 1998, scientists discovered that the expansion of the universe has been accelerating.

Lynna [10]

Dang that’s a cool fact bro

8 0

3 years ago

Read 2 more answers

According to the ideal gas law, a 1.074 mol sample of oxygen gas in a 1.746 L container at 267.6 K should exert a pressure of 13

luda_lava [24]

Answer:

% differ 1.72%

Explanation:

given data:

P_ideal = 13.51 atm

n = 1.074 mol

V = 1.746 L

T = 267.6 K

According to ideal gas law we have

$(P+ \frac{n^2 *a}{v^2}) (V - nb) = nRT$

$(P+ (\frac{1.074^2 *1.360}{1.746^2})) (1.746 - 1.074*3.183*10^{-2}) = 1.074*0.0821*267.6$

(P+0.514)(1.711) = 23.59

P_v = 13.276 atm

% differ $= \frac{ P_I - P_v}{P_I} *100$

$= \frac{13.51 - 13.27}{13.51} *100$

= 1.72%

3 0

4 years ago

During normal beating, a heart creates a maximum 3.95-mV potential across 0.305 m of a person’s chest, creating a 0.75-Hz electr

WINSTONCH [101]

Answer:

E = 0.0130 V/m.

Explanation:

The electric field is related to the potential difference as follows:

$E = \frac{\Delta V}{d}$

<u>Where:</u>

E: is electric field

ΔV: is the potential difference = 3.95 mV

d: is the distance of a person's chest = 0.305 m

Then, the electric field is:

$E = \frac{\Delta V}{d} = \frac{3.95 \cdot 10^{-3} V}{0.305 m} = 0.0130 V/m$

Therefore, the maximum electric field created is 0.0130 V/m.

I hope it helps you!

7 0

3 years ago

A 5.5kg mass is pushed with a force of 31N across a table having μk of 0.350. Find how fast it will accelerate, taking friction

Ipatiy [6.2K]

Answer:

3.66m/s^2

Explanation:

First, we need to find the friction which is F=u*N.

After that, find the resultant force by substarcting the friction from the forward force.

Lastly,using the formula F=ma, substitute in the known values of F and m to find a

4 0

3 years ago