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3 years ago

11

Given the triangle below, which of the following equations correctly representsthe relationship between a, b, and c?Triangle not

drawn to scale A cz B az 2abcos (90.)b a2 c2 2abcos (90.)

1 answer:

alukav5142 [94]3 years ago

7 0

A) it is the law of cosine

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Is this a good math essay?

astra-53 [7]

Answer:

I'm just going to assume that your answer is correct since you didn't attach the question. If you are submitting this to your teacher then you are going to want to have correct spelling and grammar. The slang usage isn't professional, but if your teacher is fine with it then you should only worry about spelling. Hope this helped you!!

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3 years ago

erik [133]

$2.=c.\\\\2\sin4x\cos4x=2\sin(2\cdot4x)=2\sin8x\\\\Used:\\\sin2\alpha=2\sin\alpha\cos\alpha$

$1.=b.\\\\\csc x-\sin x=\dfrac{1}{\sin x}-\dfrac{\sin^2x}{\sin x}=\dfrac{1-\sin^2x}{\sin x}=\dfrac{\cos^2x}{\sin x}\\\\=\dfrac{\cos x\cos x}{\sin x}=\cos x\cdot\dfrac{\cos x}{\sin x}=\cos x\cot x\\\\Used:\\\csc x=\dfrac{1}{\sin x}\\\\\sin^2x+\cos^2x=1\to\cos^2x=1-\sin^2x\\\\\cot x=\dfrac{\cos x}{\sin x}$

$3.=a.\\\\\dfrac{\sin x-1}{\sin x+1}=\dfrac{\sin x-1}{\sin x+1}\cdot\dfrac{\sin x+1}{\sin x+1}=\dfrac{\sin^2x-1^2}{(\sin x+1)^2}=\dfrac{\sin^2x-1}{(\sin x+1)^2}\\\\=\dfrac{-(1-\sin^2x)}{(\sin x+1)^2}=\dfrac{-\cos^2x}{(\sin x+1)^2}\\\\Used:\\(a-b)(a+b)=a^2-b^2\\\\\sin^2x+\cos^2x=1\to \cos^2x=1-\sin^2x$

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3 years ago

Consider the following figure where l1 and l2 are parallel and cut by transversals g1

vampirchik [111]

Answer:

helppppp

Step-by-step explanation:

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3 years ago

If a semi truck's trailer is 40 feet long, 10 feet wide, and has a height of 8 feet, what is its volume?

Temka [501]

First multiply 40 and 10 to get 400. Then multiply 400 by 8 to get 3,200.

Your answer would be: 3,200

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3 years ago

Grace is making holiday cards. Each rectangular card has an area of 28 square inches and the length is 3 inches more than the wi

melomori [17]

Length=7
Width =4
Area = length x width

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3 years ago