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3 years ago

Evaluate 5(x - 1) - 2 when x = 3. O A. -4 Ос. O D.O

Mathematics

1 answer:

12345 [234]3 years ago

4 0

Answer:

Step-by-step explanation

First you have to plug in 3 for x:

5(3-1)-2

Then using PEMDAS you would simplify that:

5(2)-2

10-2

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Vi walks five days each week.She walks the same distance on the first two days.On days three and four,Vi walks twice as long as

Alinara [238K]

Vi walks 2 miles on first day, 2 miles on second day, 8 miles on third and fourth day and 1 mile on fifth day.

Step-by-step explanation:

Let,

x be the distance walked by Vi.

Therefore,

On first day = x

Second day = x

On days three and four,Vi walks twice as long as on the first two days

Third and fourth day = 2(x+x) = 2(2x) = 4x

On fifth day = half of first day = $\frac{1}{2}x$ = 0.5x

Total distance = 13 miles

Therefore,

$x+x+4x+0.5x =13\\6.5x=13$

Dividing both sides by 6.5

$\frac{6.5x}{6.5}=\frac{13}{6.5}\\x=2$

Distance on first day = x = 2 miles

second day = x = 2 miles

third and fourth day = 4x = 4(2) = 8 miles

fifth day = 0.5x = 0.5(2) = 1 miles

Vi walks 2 miles on first day, 2 miles on second day, 8 miles on third and fourth day and 1 mile on fifth day.

Keywords: distance, addition

Learn more about distance at:

#LearnwithBrainly

6 0

3 years ago

I need help with this

NARA [144]

Answer:

all congruent

Step-by-step explanation:

5 0

2 years ago

Factorise <br> x2 - 8x + 15

lisabon 2012 [21]

Answer:

${x}^{2} - 8x + 15 \\ (x - 5)(x - 3)$

I hope I helped you^_^

4 0

2 years ago

Read 2 more answers

What are the zeros of the function below? F(x)= (x-1)(x+1)/6(x-4)(x+7)

Lisa [10]

Answer:

+1 and -1

Step-by-step explanation:

The function in this problem is:

$f(x)=\frac{(x-1)(x+1)}{6(x-4)(x+7)}$

First of all, we have to define the domain of the function, which is the set of values of x for which the function is defined.

In order to find the domain, we have to require that the denominator is different from zero, so

$6(x-4)(x+7)\neq 0$

which means:

$x\neq 4\\x\neq -7$

So the domain is all values of x, except from 4 and -7.

Now we can solve the problem and find the zeros of the function. The zeros can be found by requiring that the numerator is equal to zero, so:

$(x-1)(x+1)=0$

This is verified if either one of the two factors is equal to zero, therefore:

$x-1=0\\\rightarrow x=+1$

and

$x+1 = 0\\\rightarrow x=-1$

We see that both values are part of the domain, so they are acceptable values: so the zeros of the function are +1 and -1.

7 0

3 years ago

Which statement about BC←→ is correct?

KIM [24]

Hello!

So a tangent line is perpendicular to the radius, which means it creates a 90 degree angle with the radius of the circle. The sum of the interior angles of any triangle is 180 degrees. To determine if line BC is a tangent line, we have to determine if angle ABC is 90 degrees. Well we know the degrees of the other two angles of the triangle, so let's set up an equation:

180 = 48 + 47 + x
180 = 95 + x
85 = x

Since angle ABC must be 85 degrees (not 90), line BC is not a tangent line.

Answer:
<span>BC←→ is not a tangent line because m∠ABC ≠ 90°.</span>

3 0

3 years ago