Though these segments aren't marked congruent in the diagram, the two lines inside the circle making up the bases of the triangles are congruent as all radii are congruent. So the triangles are congruent by SAS.
Hello :
hello : <span>
1 ) if : x</span>ـــــــ> ± ∞
<span>
limf(x) = b ....(b</span>∈R) so : y=b is the equation of
the line horizontal asymptote.
<span>
2) if : x</span>ـــــــ>
a ...(a∈R)<span>
limf(x) = ± ∞
<span>so : x=a is the equation of the
line vertical asymptote.</span></span>
<span><span>hint : in this exercice : a = 2 or a = 7 but : b=2</span></span>
Answer:
Vertical: G an B. Adjacent: C and F. Supplementary: A and E. Straight: A, E. Complementary: G , B and E,A.
This is your answer (x-a).g(a)
using the LCD method.... well, there are a couple of ways, but let's simply add them up.
well, the denominators are 5x and 2x... so the only LCD will just be 10x, since it's divisible by both, so let's use that one.
