What is the difference of a number s and 6 an expression

The brain volumes (cm cubed) of 20 brains have a mean of 1111.2 cm cubed and a standard deviation of 125.3 cm cubed. Use the g

valentina_108 [34]

Answer:

Yes, the value 1411.8 cm³ is significantly high.

Step-by-step explanation:

Consider the provided information.

The brain volumes (cm cubed) of 20 brains have a mean of 1111.2 cm cubed and a standard deviation of 125.3 cm cubed.

The range rule of thumb to identify the limits separating values that are significantly low or significantly high is:

The range rule of thumb identifying significant values are as.

Significantly low values are μ-2σ

Substitute the μ = 1111.2 and σ = 125.3 in above formula.

1111.2-2(125.3)=860.6

Significantly high values are μ+2σ

Substitute the μ = 1111.2 and σ = 125.3 in above formula.

1111.2+2(125.3)=1361.8

The value is significantly high due to the value 1411.8 cm³ is not lie between the values 860.6 cm³ and 1361.8 cm³.

Hence, Yes, the value 1411.8 cm³ is significantly high.

3 0

2 years ago

Eva sees a dolphin 3.2 meters below sea level and a bird 47/10 meters above sea level. Which of the following expressions repres

Mars2501 [29]

7.9 meters apart from each other

6 0

2 years ago

Read 2 more answers

Brainly for correct answer -- step by step explination <3

prohojiy [21]

Answer:

694 ft²

Step-by-step explanation:

Calculate the area of all 6 walls, noting that the front and back faces are congruent as are the 2 side faces and top/bottom faces

area = 2(13 × 8.5) + 2(11 × 8.5) + 2(13 × 11)

= 221 + 187 + 286 = 694 ft²

4 0

3 years ago

Alim buys 2 t-shirts for $9.50 each, a 3-pack of socks for $7.95, and a pair of shoes for $7.95 and a pair of shoes for $49.95.

Usimov [2.4K]

First, I add all of my prices together.
$9.50(2)+$7.95+$7.95+$49.95= $84.85
Change 6% to a decimal = .06
Then multiply: 84.85 x .06 = $5.09
$5.09 is the sales tax
$84.85 + $5.09 = $89.94

Answer: $89.94
I hope this helps :)

3 0

3 years ago

A photoconductor film is manufactured at a nominal thickness of 25 mils. The product engineer wishes to increase the mean speed

Natali [406]

Answer:

$t=\frac{1.17-1.04}{\sqrt{\frac{0.11^2}{8}+\frac{0.09^2}{8}}}}=2.587$

$df=n_{1}+n_{2}-2=8+8-2=14$

Since is a one sided test the p value would be:

$p_v =P(t_{(14)}>2.587)=0.0108$

If we compare the p value and the significance level given $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, we have enough evidence to reject the null hypothesis on this case and the 25 mil film have a mean greater than the 20 mil film so then the claim is not appropiate

Step-by-step explanation:

Data given and notation

$\bar X_{1}=1.17$ represent the mean for the sample 1 (25 mil film)

$\bar X_{2}=1.04$ represent the mean for the sample 2 (20 mil film)

$s_{1}=0.11$ represent the sample standard deviation for the sample 1

$s_{2}=0.09$ represent the sample standard deviation for the sample 2

$n_{1}=8$ sample size selected for 1

$n_{2}=8$ sample size selected for 2

$\alpha=0.05$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if reducing the film thickness increases the mean speed of the film, the system of hypothesis would be:

Null hypothesis: $\mu_{1} \leq \mu_{2}$

Alternative hypothesis: $\mu_{1} > \mu_{2}$

If we analyze the size for the samples both are less than 30 so for this case is better apply a t test to compare means, and the statistic is given by:

$t=\frac{\bar X_{1}-\bar X_{2}}{\sqrt{\frac{s^2_{1}}{n_{1}}+\frac{s^2_{2}}{n_{2}}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{1.17-1.04}{\sqrt{\frac{0.11^2}{8}+\frac{0.09^2}{8}}}}=2.587$

P-value

The first step is calculate the degrees of freedom, on this case:

$df=n_{1}+n_{2}-2=8+8-2=14$

Since is a one sided test the p value would be:

$p_v =P(t_{(14)}>2.587)=0.0108$

If we compare the p value and the significance level given $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, we have enough evidence to reject the null hypothesis on this case and the 25 mil film have a mean greater than the 20 mil film so then the claim is not appropiate

4 0

2 years ago