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Paraphin [41]
2 years ago
5

Which of the following correctly describes the Filter procedure for managing spreadsheet data? Check all that apply.

Computers and Technology
2 answers:
saveliy_v [14]2 years ago
5 0

Answer:

Filtering procedure provides an essay and convenient way to visualize or work only with the data we desire without needing to delete those we do not need at that moment.

Filter allows you to view only the information you want to see. Only the required information is displayed at that moment once the filter criteria has been checked.

Filter temporarily hides rows of data that you do not need to view. Rows of data which aren't needed at the moment are temporarily hidden in other to allow user concentrate on the needed data.

Filter allows you to filter text and numeric data. Filtering allows for different filtering criteria, if the user requires working or viewing only on text or numeric data, it is possible with spreadsheet filter.

Explanation:

Filter allows you to view only the information you want to see.

Filter temporarily hides rows of data that you do not need to view

Filter allows you to filter text and numeric data.

Snezhnost [94]2 years ago
4 0

Answer:

what is it plz help me

Explanation:

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You are a network administrator for a large bagel manufacturer that has 32 bakeries located throughout the United States, United
Anni [7]

Answer:

See the components in explaination

Explanation:

In order to make it as IPv6, few key components should be supported, those components are given below:

The infrastructure must support the enhanced protocol StateLess Address Auto-Configuration (SLAAC).

Static addressing with DHCPv6, dynamic addressing with DHCPv6 and SLAAC are the methods used to configure the IPv6. The network administrator should able to understand and implement the IPv6 through the DHCPv6.

Other than the implementation, working of IPv4 and IPv6 are same. Therefore, the administrator need not to learn new information for its working.

As the IPv6 address length is 128-bit and purpose is for everything on line to have an IP address. It must allow the internet to expand faster devices to get internet access quickly.

The DHCPv6 is not supported by all windows. Therefore, network administrator should check the corresponding Operating system (OS) would support the DHCPv6 for IPv6.

The network administrator must have good knowledge and skills on the IPv6.

The above mentioned key components should be verified by the network administrator in order to support for IPv6 project with DHCPv6.

4 0
3 years ago
The _________ contains frequently used formatting commands that are displayed when selecting text or objects with the mouse.
kolbaska11 [484]
The Answer is toolbar.
<span>The mini or small toolbar contains frequently used formatting commands that are displayed when selecting text or objects with the mouse.
Toolbar is also known as Ribbon. It is present in computer interface design. We can see toolbar in many softwares like Microsoft office suite, web explorer, designing softwares etc. it is mostly present under the menu bar and it has many options.</span>
3 0
3 years ago
Here is the list of problems to choose from:
olya-2409 [2.1K]

Answer:

There's a parking lot that is 600m² big. The lot must be able to hold at least 3 buses and 10 cars.

Each car takes up 6m² and each bus takes up 30m².

However, there can only be 60 vehicles in the lot at any given time.

The cost to park in the lot is $2.50 per day for cars and $7.50 per day for buses. The lot must make at least $75 each day to break even.

What is a possible car to bus ratio that would allow the lot to make profit?

3 0
2 years ago
For this lab you will write a class to create a user-defined type called Shapes to represent different shapes, their perimeters
maw [93]
<h2>Answer:</h2>

<u />

========= Shape.java  ===========

//import the Scanner class

import java.util.Scanner;

public class Shape{

   //required fields

  private String shape;

   private double area;

   private double perimeter;

   //default constructor

  public Shape(){

       this.shape = "unknown";

       this.area = 0.0;

       this.perimeter = 0.0;

   }

   //constructor with one parameter

   public Shape(String shape){

       this.setShape(shape);

       this.area = 0.0;

       this.perimeter = 0.0;

   }

   //accessors and mutators

  public void setShape(String shape){

       this.shape = shape;

   }

  public String getShape(){

       return this.shape;

   }

   public double getPerimeter(){

       return this.perimeter;

   }

  public double getArea(){

       return this.area;

   }

  public void setPerimeter(Scanner scr){

       if(this.getShape().equals("circle")){

           System.out.println("Enter the radius of the circle");

           double radius = scr.nextDouble();

           this.perimeter = 2 * 3.142 * radius;

       }

       else if(this.getShape().equals("rectangle")){

           System.out.println("Enter the width");

           double width = scr.nextDouble();

           System.out.println("Enter the height");

           double height = scr.nextDouble();

           this.perimeter = 2 * (width + height);

       }

       else if(this.getShape().equals("square")){

           System.out.println("Enter the height or width");

           double height = scr.nextDouble();

           this.perimeter = 4 * height;

       }

       else if(this.getShape().equals("unknown")){

           System.out.println("You must define a shape first before calculating perimeter");

           this.perimeter = 0.0;

       }

       else {

           System.out.println("You must define a shape first before calculating perimeter");

           this.perimeter = 0.0;

       }

   }

   public void setArea(Scanner scr){

       if(this.getShape().equals("circle")){

           System.out.println("Enter the radius of the circle");

           double radius = scr.nextDouble();

           this.area = 3.142 * radius * radius;

       }

       else if(this.getShape().equals("rectangle")){

           System.out.println("Enter the width");

           double width = scr.nextDouble();

           System.out.println("Enter the height");

           double height = scr.nextDouble();

           this.area = width * height;

       }

       else if(this.getShape().equals("square")){

           System.out.println("Enter the height or width");

           double height = scr.nextDouble();

           this.area = height * height;

       }

       else if(this.getShape().equals("unknown")){

           System.out.println("You must define a shape first before calculating area");

           this.area = 0.0;

       }

       else {

           System.out.println("You must define a shape first before calculating area");

           this.area = 0.0;

       }

   }

   //Own methods

   //1. Method to show the properties of a shape

   public void showProperties(){

       System.out.println();

       System.out.println("The properties of the shape are");

       System.out.println("Shape : " + this.getShape());

       System.out.println("Perimeter : " + this.getPerimeter());

       System.out.println("Area : " + this.getArea());

   

   }

   //2. Method to find and show the difference between the area and perimeter of a shape

   public void getDifference(){

       double diff = this.getArea() - this.getPerimeter();

       System.out.println();

       System.out.println("The difference is " + diff);

   }

}

========= ShapeTest.java  ===========

import java.util.Scanner;

public class ShapeTest {

   public static void main(String [] args){

       Scanner scanner = new Scanner(System.in);

       // create an unknown shape

       Shape shape_unknown = new Shape();

       //get the shape

       System.out.println("The shape is " + shape_unknown.getShape());

       //set the area

       shape_unknown.setArea(scanner);

       //get the area

       System.out.println("The area is " + shape_unknown.getArea());

       //set the perimeter

       shape_unknown.setPerimeter(scanner);

       //get the perimeter

       System.out.println("The perimeter is " + shape_unknown.getPerimeter());

       // create another shape - circle

       Shape shape_circle = new Shape("circle");

       //set the area

       shape_circle.setArea(scanner);

       //get the area

       System.out.println("The area is " + shape_circle.getArea());

       //set the perimeter

       shape_circle.setPerimeter(scanner);

       //get the area

       System.out.println("The perimeter is " + shape_circle.getArea());

       //get the properties

       shape_circle.showProperties();

       //get the difference between area and perimeter

       shape_circle.getDifference();

   }

}

<h2>Sample output:</h2>

The shape is unknown

You must define a shape first before calculating area

The area is 0.0

You must define a shape first before calculating perimeter

The perimeter is 0.0

Enter the radius of the circle

>> 12

The area is 452.448

Enter the radius of the circle

>> 12

The perimeter is 452.448

The properties of the shape are

Shape : circle

Perimeter : 75.408

Area : 452.448

The difference is 377.03999999999996

<h2>Explanation:</h2>

The code above is written in Java. It contains comments explaining important parts of the code. Please go through the code for more explanations. For better formatting, the sample output together with the code files have also been attached to this response.

Download java
<span class="sg-text sg-text--link sg-text--bold sg-text--link-disabled sg-text--blue-dark"> java </span>
<span class="sg-text sg-text--link sg-text--bold sg-text--link-disabled sg-text--blue-dark"> java </span>
57aa40cd91dceaa5454e65fc5d209315.png
5 0
3 years ago
Number the steps to describe how Tristan can complete
Lemur [1.5K]

Answer:

  1. Cut the Television and related equipment row.
  2. Click the plus sign on the left side of the table between  the last two rows.
  3. Paste the Television and related equipment row.

Explanation:

In order to move the row, Tristan should first select the row and then cut it. This will ensure that the row will be moved completely instead of copied.

Tristan should then hover with the mouse between the last two rows and click on the plus sign on the left side. It will add a new row to the sheet. between the last two rows.

Tristan should then select the topmost cell and click paste. The television row will be pasted there and Tristan would have successfully moved it.

4 0
3 years ago
Read 2 more answers
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