Answer:

Step-by-step explanation:
step 1
In the right triangle ABC
Applying the Pythagoras Theorem fin the hypotenuse AC

substitute



step 2
we know that
If two figures are similar, then the ratio of its corresponding sides is equal
so

substitute and solve for CE

step 3
Find the length of segment AE
AE=AC+CE
substitute the values

The question is incomplete:
Before leaving to visit Mexico, Levant traded 270 American dollars and received 3,000 Mexican pesos. When he returned from Mexico, he had 100 pesos left.
How much will he receive when he exchanges these pesos for dollars?
Answer:
9 dollars
Step-by-step explanation:
To find the amount that Levant will receive when he exchanges these pesos for dollars, you can use a rule of three using the information provided:
270 dollars → 3,000 Mexican pesos
x ← 100 Mexican pesos
x=(270*100)/3,000=9 dollars
According to this, the answer is that he will receive 9 dollars.
Answer:
2x+8-2y
Step-by-step explanation:
4x-2x+5+3-2y
2x+8-2y
Well, we could try adding up odd numbers, and look to see when we reach 400. But I'm hoping to find an easier way.
First of all ... I'm not sure this will help, but let's stop and notice it anyway ...
An odd number of odd numbers (like 1, 3, 5) add up to an odd number, but
an even number of odd numbers (like 1,3,5,7) add up to an even number.
So if the sum is going to be exactly 400, then there will have to be an even
number of items in the set.
Now, let's put down an even number of odd numbers to work with,and see
what we can notice about them:
1, 3, 5, 7, 9, 11, 13, 15 .
Number of items in the set . . . 8
Sum of all the items in the set . . . 64
Hmmm. That's interesting. 64 happens to be the square of 8 .
Do you think that might be all there is to it ?
Let's check it out:
Even-numbered lists of odd numbers:
1, 3 Items = 2, Sum = 4
1, 3, 5, 7 Items = 4, Sum = 16
1, 3, 5, 7, 9, 11 Items = 6, Sum = 36
1, 3, 5, 7, 9, 11, 13, 15 . . Items = 8, Sum = 64 .
Amazing ! The sum is always the square of the number of items in the set !
For a sum of 400 ... which just happens to be the square of 20,
we just need the <em><u>first 20 consecutive odd numbers</u></em>.
I slogged through it on my calculator, and it's true.
I never knew this before. It seems to be something valuable
to keep in my tool-box (and cherish always).