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DerKrebs [107]
3 years ago
12

Writing the Equation of a Parallel Line

Mathematics
1 answer:
Softa [21]3 years ago
3 0
2x + 5y = - 5 is the answer. I m very expert in maths . So ask me your doubt. I can help
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In isosceles ΔABC, AC = BC, AB = 6 in, CD ⊥ AB, and CD = 3 in. Find the perimeter of the isosceles triangle.
Hoochie [10]

Answer:

Step-by-step explanation:

Consider the given triangle ABC, we have AC = BC, AB = 6 in, CD ⊥ AB, and CD = 3 in. Using ΔCDB, we have

(CB)^{2}=(CD)^{2}+(DB)^{2}

(CB)^{2}=(3)^{2}+(3)^{2}

CB=\sqrt{9+9}

CB=\sqrt{18}in

Therefore, CB=CA=\sqrt{18}in (Given)

Now, Perimeter of an isosceles triangle is given By: 2a+b

⇒2(\sqrt{18})+6=2(4.24)+6=8.48+6=14.48in

which is the required perimeter of isosceles triangle.

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