Answer:
1.00 m is a more accurate measured length.
Explanation:
Denote length of the table by L.
For L=1.0 m, there is one significant digit after the decimal.
Care 1: When one more significant digit after decimal considered, the exact number can be from 0.95 to 1.05.
So, the possible span of error
For L=1.00 m, there is two significant digits after the decimal.
Case 2: When one more significant digit after decimal considered, the exact number can be from 0.095 to 1.005.
So, the possible span of error
Case 3: For L=1.000 m, there is three significant digits after the decimal.
When one more significant digit after decimal considered, the exact number can be from 0.0095 to 1.0005.
So, the possible span of error
As
So, the least error is in the third case when L=1.00m, hence, L= 1.00m is more accurate.
Answer:
Explanation:
We know that the gravity on the surface of the moon is,
<u>Gravity at a height h above the surface of the moon will be given as:</u>
..........................(1)
where:
G = universal gravitational constant
m = mass of the moon
r = radius of moon
We have:
Now put the respective values in eq. (1)
is the gravity on the moon the earth-surface.
I believe this is what you have to do:
The force between a mass M and a point mass m is represented by
So lets compare it to the original force before it doubles, it would just be the exact formula so lets call that F₁
So F₁ = G(Mm/r^2)
Now the distance has doubled so lets account for this in F₂:
F₂ = G(Mm/(2r)^2)
Now square the 2 that gives you four and we can pull that out in front to give
F₂ = G(Mm/r^2)
Now we can replace G(Mm/r^2) with F₁ as that is the value of the force before alterations
now we see that:
F₂ = F₁
So the second force will be 0.25 (1/4) x 1600 or 400 N.