Answer:
<u>Average Velocity:</u>
When a body covers some displacement moving from point A to B, in a given time,t. Then dividing the total distance covered by the time taken to complete the displacement is called as the average velocity of that car.
We can calculate the average velocity of car by subtracting the initial displacement of a body,s₁ from the final displacement position of the body, s₂. And then dividing by the initial time,t₁ been subtracted from the final time,t₂.
We will get the required results, now if we want to obtain the results in the final three seconds then, we can have the following explanation to that as given.
Explanation:
Lets say, that we have the car moving for 10 seconds and then it stops at the eleventh second of the trip on final position, of the displacement. Then we divide the whole trips into small segments, as we will have the different velocity at each interval but, the velocity is unknown at the last 3 seconds is unknown=?.
- Total time taken, Δt= 11 seconds,
- Then lets say the velocity at the 8th second is , v=25 m/s,then
- Δv=x₂-(25)/11-0,⇒Δv=x₂-25/11,
I think it’s C but not sure..
T=Vf-Vi/s
25m/s -15m/s/ 125m
10m/s /125m
=0.08s
I hope it’s correct !
Answer
ω2=82.1 rpm
Explanation:
given required
m1=2.3 kg ω2=?
m2+m3=0.5kg
r1=10 cm
ω1=100 rpm
solution
Using the application of conservation of angular momentum we can solve as follows/
L before collision= L after collision
m1r²ω1=(m1+m2+m3)r²ω2
2.3 kg×0.1² m²×100 rpm=(2.3 kg+0.5 kg)×0.1²m²×ω2
2.3 rpm=0.028×ω2
ω2=82.1 rpm
Answer:The force of buoyancy equals density of liquid times acceleration due to gravity times volume of liquid replaced. So buoyancy is directly proportional to gravity, and you would float just as well in 5G as 1G. ... A simpler way to look at it is: you float because gravity attracts water more than it attracts your body.
Explanation: i dont know if this helps i hope it does have a nice day.
