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rusak2 [61]
3 years ago
11

If Usain bolt ran 200 meters in 19.30 seconds, how many meters did he run per second

Mathematics
1 answer:
Tanya [424]3 years ago
7 0
200 / 19.30 = 10.36

Usain ran 10.36 meters per second
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PLS SOLVE THIS QUESTION. The first one to get it right get's a brainliest.
Tanya [424]

Answer:

-3

Step-by-step explanation:

You have get a graphing calculator and press y=.

Then you would type in the equation.

Then click second, graph after you type the equation.

Then scan through the t graph for the value that causes the equation to be 0

4 0
4 years ago
Four streets enter a traffic circle at points A B C and D name six arcs formed by the streets.
lilavasa [31]
Arcs are just sections of the circle
so lets say you had a pizza

and you put some points on the crust, the legnth of the crust from point to point is that arc

example
if you put poins A and B, then arc AB is the crust between points A and B

arcs can include other points as well
 and arc AB=arc BA


so
I wil name easy arcs first
arc AB
arc BC
arc CD
ard DA

now ones that include others
arc AC
arc BD

so the arcs you might want to list are
 
arc AB
arc BC
arc CD
ard DA
arc AC
arc DB

5 0
4 years ago
Can someone help me with these problems and explain them as well please
olga_2 [115]

Answer:

b=112°

Step-by-step explanation:

two complementary angles

b=180°-68°=112°

sum of 2 angles is

x= 35°+25°=60°

7 0
3 years ago
Read 2 more answers
PLEASE help for brainliest
MakcuM [25]

<em>1.) </em><em>x</em>

<em />

<em>2.) </em><em>f(x)</em>

<em />

<em>3.) </em><em>the output (y-value) when x = 2</em>

<em />

<em>4.) </em><em>f(2) = 2</em>

5 0
3 years ago
On a December day, the probability of snow is 0.30. The probability of a "cold" day is 0.50. The probability of snow and "cold"
Margarita [4]

Answer:

Yes, snow and cold weather are independent.

Step-by-step explanation:

We are given the following in the question:

C: Cold weather

S: Snow

P(C) = 0.50

P(S) =0.30

P(S\cap C) = 0.15

We have to check whether snow and cold whether are independent events.

If the events A and B are independent then,

p(A\cap B) = P(A)\times P(B)

Checking,

p(S\cap C) = P(S)\times P(C)\\0.15 = 0.30\times 0.50

Thus, the two events are independent.

For mutually exclusive events

P(A\cap B) = 0

Thus, the given events are not mutually exclusive.

8 0
3 years ago
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