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3 years ago

Please help me with this math problem, urgent please

Mathematics

2 answers:

ivann1987 [24]3 years ago

7 0

Answer:

(5z +2) (z+1)

Step-by-step explanation:

5z^2 +7z +2

(5z +2) (z+1)

The first term when multiplied out is 5z^2 The last term is 2

The middle term is 2z+5z = 7z so this is the correct factorization

djverab [1.8K]3 years ago

6 0

problem decoded dude

follow meh

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please help me with this one and more thru the comments I don't have that many points please do it I'm begging u

zvonat [6]

Step-by-step explanation:

(example)

Think of it this way:

If joe caught 1 fish only

and bonita caught four more than joe

that means that she caught 5 fish in total.

(for the question)

This means that Bonita caught four more fish than Joe.

j + 4 = bonita

j = joe

3 0

3 years ago

5. Mark's brother is five years older than Mark.

AleksAgata [21]

Answer:

Step-by-step explanation:

Let's say Mark is M and his brother is B.

M+5=B

M+B=23

Now we can solve using subsitution.

M+M+5=23

(Subtract 5 from both sides)

2M=18

M=9

Hope this helped!

8 0

3 years ago

Given that sec0=-37/12 what is the value of cot0, for Pi/2<0

inysia [295]

Answer:

Step-by-step explanation:

12/35

3 0

3 years ago

Driving 60 miles per hour between Charleston and Columbia, which are 120 miles apart.

Sav [38]

All the hours together are 6 hours

8 0

3 years ago

Evaluate the following integral using trigonometric substitution

serg [7]

Answer:

The result of the integral is:

$\arcsin{(\frac{x}{3})} + C$

Step-by-step explanation:

We are given the following integral:

$\int \frac{dx}{\sqrt{9-x^2}}$

Trigonometric substitution:

We have the term in the following format: $a^2 - x^2$ , in which a = 3.

In this case, the substitution is given by:

$x = a\sin{\theta}$

$dx = a\cos{\theta}d\theta$

In this question:

$a = 3$

$x = 3\sin{\theta}$

$dx = 3\cos{\theta}d\theta$

$\int \frac{3\cos{\theta}d\theta}{\sqrt{9-(3\sin{\theta})^2}} = \int \frac{3\cos{\theta}d\theta}{\sqrt{9 - 9\sin^{2}{\theta}}} = \int \frac{3\cos{\theta}d\theta}{\sqrt{9(1 - \sin^{\theta})}}$

We have the following trigonometric identity:

$\sin^{2}{\theta} + \cos^{2}{\theta} = 1$

$1 - \sin^{2}{\theta} = \cos^{2}{\theta}$

Replacing into the integral:

$\int \frac{3\cos{\theta}d\theta}{\sqrt{9(1 - \sin^{2}{\theta})}} = \int{\frac{3\cos{\theta}d\theta}{\sqrt{9\cos^{2}{\theta}}} = \int \frac{3\cos{\theta}d\theta}{3\cos{\theta}} = \int d\theta = \theta + C$

Coming back to x:

We have that:

$x = 3\sin{\theta}$

$\sin{\theta} = \frac{x}{3}$

Applying the arcsine(inverse sine) function to both sides, we get that:

$\theta = \arcsin{(\frac{x}{3})}$

The result of the integral is:

$\arcsin{(\frac{x}{3})} + C$

8 0

3 years ago