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2 years ago

A line contains the two points plotted in the coordinate plane below.

Mathematics

1 answer:

Andrew [12]2 years ago

6 0

Answer:

The slope would be 3.

Step-by-step explanation:

The formula for finding slope is $\frac{y1-y2}{x1-x2}$
We can plug these numbers into the equation by doing $\frac{1--5}{2-0}$
1--5 is equal to 1+5, which is 6.
2-0 is equal to 2.
$\frac{6}{2}$ is 3, which is how you get your answer.
I hope this helps! :)

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Four out of seven spectators at a different game are routing for North Star Academy. If there are 68 people rooting for North st

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68 divided by 4 is 17 and 17 times 7 (the amount of people watching) is 119

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3 years ago

A line parallel to the graph of 3x+2y=6 and contains the point (6,-3)

FromTheMoon [43]

The Equation of the Line that Passes through (4, 2) and is Parallel to 3x – 2y = –6 is 3x – 2y = 8

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2 years ago

Add an intersection the red light times normally distributed by the mean of three minutes and a standard deviation of .25 minute

Soloha48 [4]

95% of red lights last between 2.5 and 3.5 minutes.

<u>Step-by-step explanation:</u>

In this case,

The mean M is 3 and
The standard deviation SD is given as 0.25

Assume the bell shaped graph of normal distribution,

The center of the graph is mean which is 3 minutes.

We move one space to the right side of mean ⇒ M + SD

⇒ 3+0.25 = 3.25 minutes.

Again we move one more space to the right of mean ⇒ M + 2SD

⇒ 3 + (0.25×2) = 3.5 minutes.

Similarly,

Move one space to the left side of mean ⇒ M - SD

⇒ 3-0.25 = 2.75 minutes.

Again we move one more space to the left of mean ⇒ M - 2SD

⇒ 3 - (0.25×2) =2.5 minutes.

The questions asks to approximately what percent of red lights last between 2.5 and 3.5 minutes.

Notice 2.5 and 3.5 fall within 2 standard deviations, and that 95% of the data is within 2 standard deviations. (Refer to bell-shaped graph)

Therefore, the percent of red lights that last between 2.5 and 3.5 minutes is 95%

8 0

3 years ago

Tony separates a number of paintbrushes, x, into 3 equally sized groups. He claims that this is the same as making a group 1/3 t

DochEvi [55]

Answer:

Size of each group = $\frac{x}{3}$

Step-by-step explanation:

Total number of paint brushes = x

Since each the three groups are equally sized, to get the number of paintbrushes in a group, we will have to divide the total number of paint brushes by 3

∴ We have, number of paint brushes in a group = $\frac{Total number of paintbrushes}{3}\\$

= $\frac{x}{3}$

this is also the same thing as saying $\frac{1}{3}$ × $\frac{x}{1}$

This shows that the size of the new group is the same as $\frac{1}{3}$ the size of the original group

4 0

3 years ago

A professor finds that the average SAT score among all students attending his college is 1150 ± 150 (μ ± σ). He polls his class

solniwko [45]

Answer:

Step-by-step explanation

Hello!

Be X: SAT scores of students attending college.

The population mean is μ= 1150 and the standard deviation σ= 150

The teacher takes a sample of 25 students of his class, the resulting sample mean is 1200.

If the professor wants to test if the average SAT score is, as reported, 1150, the statistic hypotheses are:

H₀: μ = 1150

H₁: μ ≠ 1150

α: 0.05

$Z= \frac{X[bar]-Mu}{\frac{Sigma}{\sqrt{n} } } ~~N(0;1)$

$Z_{H_0}= \frac{1200-1150}{\frac{150}{\sqrt{25} } } = 1.67$

The p-value for this test is 0.0949

Since the p-value is greater than the level of significance, the decision is to reject the null hypothesis. Then using a significance level of 5%, there is enough evidence to reject the null hypothesis, then the average SAT score of the college students is not 1150.

I hope it helps!

7 0

3 years ago