Assuming the coin is fair, probability of getting one tail is 50%, probability of getting two tails in a row is 50%*50% = 25% or 1/4
Put into slope intercept form, y=mx+b where m=slope
p=-2q+6
slope is -2
subsitute values for q and get values for p
q=0, p=6
(q,p)
(0,6)
(1,4)
p=q+4
slope is 1
subsitutte
q=0,p=4
(q,p)
(0,4)
(1,5)
below are the graphs
Answer:
x < 7
Step-by-step explanation:
Flip the equation to make it easier: x - 6 < 1
Move 6 to the other side and change sign: x < 1 + 6
Do simple addition: x < 7
Answer: 1/67600
Step-by-step explanation:
probability that the code is 43MZ:
Probability = (Total Required outcome / total possible outcomes)
Possible outcomes (digit) = (00,.............. ..., 99)
2.) possible outcomes (alphabet) = (A, B,............... .., Z)
P(43MZ) = P(43) × P(M) × P(Z)
P(43) = 1/100
P(M) = 1/26
P(Z) = 1/26
THEREFORE ;
P(43MZ) = (1/100) × (1/26) × (1/26) = 1/67600
Y: x-1 that is the answer. I think so.