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Lorico [155]
3 years ago
5

I need this answer ASAP pls someone help ASAP work shown Worth 10 pts

Mathematics
1 answer:
zlopas [31]3 years ago
4 0

Answer:

5c² + 4c - 4

Step-by-step explanation:

Subtract the shaded area from the area of the outer rectangle, that is

(2c + 3)(3c - 2) - (c + 2)(c - 1) ← expand both pairs of factors using FOIL

= 6c² + 5c - 6 - (c² + c - 2) ← distribute parenthesis by - 1

= 6c² + 5c - 6 - c² - c + 2 ← collect like terms

= 5c² + 4c - 4

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Which of the following is the simplified form of the seventh root of x times the seventh root of x times the seventh root of x ?
Studentka2010 [4]
When multiplying numbers of the same base , we add the powers.
Example:
2^2 * 2^3 = 2^(2+3) = 2^5

For the givens:
The seventh root of x can be written as x^(1/7)
Now, we need to multiply x^(1/7) by x^(1/7) by x^(1/7)
These numbers have the same base which is "x", therefore, we will just add the power.
This means that:
x^(1/7) * x^(1/7) * x^(1/7) = x^(1/7 + 1/7 + 1/7) = x^(3/7)

Therefore, the correct choice is the first one: x^(3/7)

5 0
3 years ago
6 cakes cost £6.48 how much does one cost
sveta [45]
6.48 divide by 6 and u will get the answer
8 0
3 years ago
Help me please !<br> 4,5 and 6
andreev551 [17]

9514 1404 393

Answer:

  4a. ∠V≅∠Y

  4b. TU ≅ WX

  5. No; no applicable postulate

  6. see below

Step-by-step explanation:

<h3>4.</h3>

a. When you use the ASA postulate, you are claiming you have shown two angles and the side between them to be congruent. Here, you're given side TV and angle T are congruent to their counterparts, sides WY and angle W. The angle at the other end of segment TV is angle V. Its counterpart is the other end of segment WY from angle W. In order to use ASA, we must show ...

  ∠V≅∠Y

__

b. When you use the SAS postulate, you are claiming you have shown two sides and the angle between them are congruent. The angle T is between sides TV and TU. The angle congruent to that, ∠W, is between sides WY and WX. Then the missing congruence that must be shown is ...

  TU ≅ WX

__

<h3>5.</h3>

The marked congruences are for two sides and a non-included angle. There is no SSA postulate for proving congruence. (In fact, there are two different possible triangles that have the given dimensions. This can be seen in the fact that the given angle is opposite the shortest of the given sides.)

  "No, we cannot prove they are congruent because none of the five postulates or theorems can be used."

__

<h3>6.</h3>

The first statement/reason is always the list of "given" statements.

1. ∠A≅∠D, AC≅DC . . . . given

2. . . . . vertical angles are congruent

3. . . . . ASA postulate

4. . . . . CPCTC

8 0
3 years ago
-3 + n = 6n + 22 ; Solve for n.
anygoal [31]

Answer:

-3 + n = 6n + 22

-1n on both sides

-3=5n+22

-22 on both sides

-25=5n

divided by 5

-5=n

Step-by-step explanation:

6 0
3 years ago
What is the solution the solution to x/-1 &gt; -6
wlad13 [49]

Answer:

x < 6

Step-by-step explanation:

x/-1 > -6

x < (-6) * (-1)

so, x < 6

5 0
3 years ago
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