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Stolb23 [73]
3 years ago
13

.!.$.!.!.’!!.!!.!.!need help

Mathematics
2 answers:
VLD [36.1K]3 years ago
8 0

Answer:

8.) x×6=y

Step-by-step explanation:

1×6=6

2×6=12

4×6=24

5×6=30

25×6=150

For each of the others, multiply the value of x times the CoP for the y value and divide the value of y by the CoP to get the x value. I've attached the work for number 9.

artcher [175]3 years ago
7 0

oml! ill try give me a min tho

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y = \frac{4}{3}x-5

Step-by-step explanation:

As the line is perpendicular to y=-\frac{3}{4} x + 2, we know that the slope of the line is \frac{4}{3}. As it passes through (3, - 1), we know that it should be y = \frac{4}{3}x-5.

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The table shows the approximate population of Virginia for 5 years. If the trend continues, which could
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Step-by-step explanation:

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How would I do this only the bottom part
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The third angle would be
8 0
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What is the distance between the point (10,12) and (-4,-36)
dimulka [17.4K]
Well using distance formula

d \:  =  \sqrt{(x {}^{2} }  - x {}^{1} ) + (y {}^{2}  + y {}^{1} )
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4 0
4 years ago
El costo de producir 10 juegos de video al día es de 350 dólares , mientras que producir 30 juegos del mismo tipo al día cuestan
Dovator [93]

Answer:

El coste de producir un juego de vídeo es de 125 dólares.

Step-by-step explanation:

(This exercise is written in Spanish and is incomplete. Complete statement will be presented below)

El costo de producir 10 juegos de video al día es de 350 dólares , mientras que producir 30 juegos del mismo tipo al día cuestan 850 dólares . Si suponemos un modelo lineal como el descrito anteriormente , determine:

¿Cuál es el costo de producir un juego de vídeo?

(Explanation will be held in Spanish)

El modelo lineal es un polinomio de primer orden de la forma:

y = a\cdot x + b

Donde:

x - Variable independiente (eje x - Cantidad de juegos de vídeo producidos - Adimensional)

y - Variable dependiente (eje y - Coste de producción de juegos de vídeo - Dólares)

a - Pendiente de la función.

b - Intercepto en el eje y.

Dados los dos costes para dos cuotas distintas de producción, se construye el siguiente sistema de ecuaciones lineales:

10\cdot a + b = 350

30 \cdot a + b = 850

Se resuelve el sistema con algo de manipulación algebraica:

(30\cdot a + b) - (10\cdot a + b) = 850 - 350

20 \cdot a = 500

a = 25

Luego:

b = 850 - 30\cdot a

b = 100

La ecuación lineal es:

y = 25\cdot x +100

Finalmente, el coste de producir un juego de vídeo es:

y = 25 \cdot (1) + 100

y = 125

El coste de producir un juego de vídeo es de 125 dólares.

7 0
4 years ago
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