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jeka94
3 years ago
7

Solve the equation below

27(x-2)}=3" alt="\sqrt[5]{27(x-2)}=3" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
Mariana [72]3 years ago
8 0

Answer:

x = 11

Step-by-step explanation:

Raising both sides to the fifth power, we get:

27(x - 2) = 3⁵

x - 2 = 3⁵ / 27

x - 2 = 3⁵ / 3³

x - 2 = 3⁽⁵⁻³⁾ = 3² = 9

x = 11

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Parallelogram JKLM has vertices J(-1, 6), K(0, 9), L(6, −3), and M(3, −3). What is the coordinates of the image if the parallelo
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Answer: (\dfrac13,-2),\ (0,-3),\ (-2,1),\ (-1,1) .

Step-by-step explanation:

Transformation rule for dilation:

(x,y)\to(kx,ky) , where k = scale factor

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Vertices after dilation:

(-1,6)\to(-1\times\dfrac{-1}{3},6\times\dfrac{-1}{3})=(\dfrac13,-2)

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Hence, the coordinates of the image if the parallelogram = (\dfrac13,-2),\ (0,-3),\ (-2,1),\ (-1,1) .

8 0
3 years ago
I) Consider the following figure,<br><br> ​<br><br> ​<br><br> ​
qwelly [4]

Step-by-step explanation:

If PQRS is a quadrilateral inscribed in a circle, then the opposite angles of the quadrilateral are <u>supplementary</u><u>.</u>

y + 68° = 180° { being opposite angles of cyclic quadrilateral }

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Hope it will help :)❤

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