Answer:
a. the environmental variance (VE) = 3.5 g ²
b. 17.5 g ² for population
c. the heritability of broad sense (H2) = 0.83
Explanation:
a.With the information we have we can infer that environmental factors influence A, which is considered isogenic, thus, the environmental variance (VE) = 3.5 g ²
b.When studying population B, comparing it without environmental changes with respect to population A, we found that its total variance (VT) = 21.0g ²
We generate the following formula with the data obtained previously to find the genetic variation
VT = VE + VG
then VG = VT-VE
replacing data:
VG = 21.0 - 3.5 = 17.5 g ² for population
c. Regarding the heritability of broad sense (H2) in population B, we can reach the result with the data previously obtained like this:
H2 = VG / VT = 17.5 / 21.0 = 0.83
The proteins exhibit four levels of organization:
1. Primary structure: It refers to a sequence of amino acids join together by the peptide bonds to produce a polypeptide chain.
2. Secondary structure: It is a localized twisting of the polypeptide chain by producing a hydrogen bond. Two types are formed, that is, the alpha helix and beta pleated sheet.
3. Tertiary structure: It refers to the three-dimensional composition of a polypeptide chain. The folding is not regular as it is in secondary composition. It produces ionic bonds, hydrophobic interactions, disulfide bond, and hydrogen bond amongst the polypeptide chains.
4. Quaternary structure: It comprises an amalgamation of two or more polypeptide chains that functions as a single functional unit. The bonds are identical as in tertiary composition.
Thus, the levels of secondary, tertiary, and quaternary protein structure would get affected if all the hydrogen bonding associations were inhibited.
Cells formed by mitosis are identical to each other and to the parent cell.
Answer:
Its aerobic, thats the esiest question. also give brainliest plz
Explanation:
