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3 years ago

1. Balance the following decomposition of NaHCO3. NaHCO3 → Na2CO3 + CO2 + H2O

Chemistry

1 answer:

Vika [28.1K]3 years ago

6 0

Answer: Count all the atoms on each side of the chemical equation once you know how how many of each type of atom.

Explanation:you can only change the coefficients (the number in front of the atom )

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Complete combustion of 2.0 metric tons of coal to gaseous carbon dioxide releases 6.6X10¹⁰ J of heat. Convert this energy to

Taya2010 [7]

First of all we should know that, 1 Joule = 0.000239 kilocalories.

So, 6.6× $10^{10}$ J = 6.6× $10^{10}$ × 0.000239 kilocalories

6.6× $10^{10}$ J = 15774000 kilocalories

= 1.58 × $10^{7}$ kilocalories

One joule is described as the quantity of electricity exerted when a pressure of 1 newton is implemented over a displacement of 1 meter. Within the SI machine, the unit of labor or electricity is the Joule.

The kilocalorie, or meals calorie, is the quantity of warmth required to elevate one kilogram of water 1 °C. warmness capability is the amount of heat required to raise one gram of material 1 °C beneath steady pressure. A kilocalorie is the amount of warmth required to raise the temperature of 1 kilogram of water one diploma Celsius.

Learn more about joule here:-

brainly.com/question/490326

#SPJ4

6 0

2 years ago

Write the balanced neutralization reaction that occurs between H 2 SO 4 and KOH in aqueous solution. Phases are optional. neutra

Mariulka [41]

Answer:

0.168 M

Explanation:

First, this is a reaction between the a strong base and a strong acid, therefore, we do not have to count with the acid constant of equilibrium. This reaction is taking place completely and occurs a neutralization, which is the following reaction:

H₂SO₄(aq) + 2KOH(aq) <------> K₂SO₄(s) + 2H₂O(l)

Now that we have the reaction, we can go to the second part of the question.

To calculate the remaining concentration after neutralization, we need to calculate the moles of the reactants and determine which is the limiting reactant.

The moles of the reactants:

moles A = 0.42 * 0.15 = 0.063 moles

moles B = 0.210 * 0.1 = 0.021 moles

Now that we have the moles, let's calculate the limiting reactant:

H₂SO₄(aq) + 2KOH(aq) <------> K₂SO₄(s) + 2H₂O(l)

If:

1 moles A ---------> 2 moles B

0.063 A -----------> X

X = 0.063 * 2 = 0.126 moles of B

However, we only have 0.021 moles of base, so, this is the limiting reactant.

Now that we know this, let's see the remaining moles of the acid, after the base reacts completely:

moles of A remaining = 0.063 - 0.021 = 0.042 moles

Finally to get the concentration, we have the volume of acid and the base together, so, the final volume is 0.25 L:

C = 0.042 / 0.25 = 0.168 M

This is the final concentration of the acid

3 0

3 years ago

5.080 x 1016 molecules of hydrogen to moles

lawyer [7]

For this problem, to determine the number of moles given the number of molecules, we use the Avogadro's number. This is an empirical value that relates the number of particles (e.g. atoms, molecules, sub-particles) in one mole of any substance. The value is 6.022×10²³ molecules/mol.

5.080×10¹⁶ molecules * 1 mol/6.022×10²³ molecules = <em>8.436×10⁻⁸ moles of hydrogen</em>

3 0

3 years ago

When transition metal atoms lose electrons to form ions, the electrons come first from the highest filled s atomic orbital. With

kap26 [50]

The atomic number of Fe= 26

The electronic configuration of Fe will be

1s2 2s2 2p6 3s2 3p6 4s2 3d6

When it loses two electrons to form ferrous ion (Fe(II)) the electrons will be loose by 4s orbital first

So the electronic configuration of Fe^+2 ion will be

1s2 2s2 2p6 3s2 3p6 3d6

Hence there are six electrons in 3d orbital of iron dipositive ion

Now the the electrons in 3d orbital will be like:

so there are four unpaired electrons

5 0

3 years ago

What moon phase occurs 3-4 days after a waning gibbous

Artyom0805 [142]

Third quarter (or last quarter)

4 0

4 years ago