3 years ago

If the length of a square is 10 feet what is the area?

1 answer:

8 0

The area of a square is length x width, but as all sides of a square are equal, then you can simply square the length of one side of the square.
The length of the square in your problem is 10 feet, so all sides have a length of 10 feet. You can write the problem for getting the area as 10x10 or 10-squared (10^2).
The answer would be 100 feet.

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The angle bisector of ∠ACD in rhombus ABCD makes a 64° angle with the diagonal BD. Find the measure of ∠BAD.

saveliy_v [14]

The complete question in the attached figure

we know that
the diagonals of a rhombus intersect to form right angles,
so
angle ACE is ----------> (90°-64°)-----------> 26°
ACE is the angle bisector of ACD, this means that ACD is ---------> 26 x 2 = 52°

The diagonals are angle bisectors to the opposite corners
so
ACD = ACB = 52°
and
BCD = 52 x 2 = 104°
For a rhombus, opposite angles are equivalent,
so
BAD = BCD = 104°

the answer is
angle BAD=104°

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