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vodka [1.7K]
4 years ago
8

What’s the square root of 15

Mathematics
2 answers:
viva [34]4 years ago
4 0

Answer:3.87298334621

Step-by-step explanation:

Mumz [18]4 years ago
3 0

Answer:

square root of 15 is 3.87 or 3.9 when rounded to nearest tenth

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Simplify (2×-2y)(2y+8)=
Murrr4er [49]
(x - y) • (y + 4)

Have a great day!
6 0
3 years ago
Can some on help me please??
erma4kov [3.2K]

Answer:

Frequency is 2, 2 and 3.

Step-by-step explanation:

Temp in 101 to 106 - In this range only 2 temperature is there 104 and 104 in 2 cities. so frequency is 2.

Temp in 107 to 112 - In this range only 2 temperature is there 107 and 112 in 2 cities. so frequency is 2.

Temp in 113 to 118 - In this range only 3 temperature is there 114, 117 and 118 so frequency is 3.

5 0
3 years ago
Read 2 more answers
The mean of a population is 74 and the standard deviation is 16. The shape of the population is unknown. Determine the probabili
bulgar [2K]

Answer:

a

 P(X  >  75)=  0.35402

b

P(72 <  X  <  75 ) = 0.2529

c

P( X  <  74.7)  = 0.74041

Step-by-step explanation:

From the question we are told that

  The population mean is  \mu =  74

  The population standard deviation is  \sigma  =  16

 Considering question a  

    The sample size is  n  =  36  

Generally the standard error of mean is mathematically represented as

     \sigma_{x} =  \frac{\sigma  }{\sqrt{n} }

=>  \sigma_{x} =  \frac{16}{\sqrt{36} }

=>  \sigma_{x} = 2.67

Generally the probability that a  random sample of size 36 yielding a sample mean of 75 or more is mathematically represented as

     P(X  >  75) =  P( \frac{X -  \mu  }{ \sigma_{x}} >  \frac{75 -  74}{ 2.67 }  )

\frac{X -\mu}{\sigma }  =  Z (The  \ standardized \  value\  of  \ X )

   P(X  >  75) =  P(Z >  0.3745   )

From the z table  the area under the normal curve representing 0.3745 to the right is  

     P(Z >  0.3745   ) =  0.35402

=>   P(X  >  75)=  0.35402

 Considering question b  

    The sample size is  n  =  104

Generally the standard error of mean is mathematically represented as

     \sigma_{x} =  \frac{\sigma  }{\sqrt{n} }

=>  \sigma_{x} =  \frac{16}{\sqrt{104} }

=>  \sigma_{x} = 1.5689

Generally the probability that a random sample of size 104 yielding a sample mean  between 72 and 75 is mathematically represented as

      P(72 <  X  <  75 ) =  P(\frac{72 - 74 }{1.5689}  <  \frac{X -  \mu }{\sigma_{x}}  < \frac{75 - 74 }{1.5689}   )

=>   P(72 <  X  <  75 ) =  P(-1.275 < Z < 0.375   )

=>   P(72 <  X  <  75 ) =  P(Z < 0.375   ) -  P(Z <  -1.275)

From the z table  the area under the normal curve representing -1.275 to to the left is

   P(Z <  -1.275) =0.10115

=> P(72 <  X  <  75 ) = 0.35402  -  0.10115

=> P(72 <  X  <  75 ) = 0.2529

Considering question c

    The sample size is  n  =  217

Generally the standard error of mean is mathematically represented as

     \sigma_{x} =  \frac{\sigma  }{\sqrt{n} }

=>  \sigma_{x} =  \frac{16}{\sqrt{217} }

=>  \sigma_{x} = 1.086

Generally the probability that a  random sample of size 217 yielding a sample mean of less than 74.7 is mathematically represented as

       P( X  <  74.7) =  P(\frac{X -  \mu }{\sigma_x}  < \frac{ 74.7 -  74 }{ 1.086 })

=>   P( X  <  74.7) =  P(Z < 0.6446 )

From the z table  the area under the normal curve representing 0.6446  to to the left is

     P(Z < 0.6446 )  =  0.74041

=>  P( X  <  74.7)  = 0.74041

8 0
3 years ago
Two perpendicular lines intersect on the -axis. The equation of one line is y- 4x-6=0. Determine the equation of the other line.
Kay [80]

Answer:

y = -\frac{1}{4}x + 6 or y = -\frac{1}{4}x - 0.375

Step-by-step explanation:

For 2 lines to be perpendicular, their slopes must be <u>negative reciprocals</u>. In order to find the perpendicular of y - 4x - 6 = 0:

SLOPE INTERCEPT FORM: y = 4x + 6

SLOPE OF LINE A: m=4

SLOPE OF LINE B (the one you are looking for): m=-\frac{1}{4}

Since I don't know if you meant that they intercept on the x or y axis I will do both.

<u>y-axis</u>

y-6=-\frac{1}{4}(x-0)

y = -\frac{1}{4}x+6

<u>x-axis</u>

y-0=-\frac{1}{4}(x-1.5)

y=-\frac{1}{4}x-0.375

7 0
3 years ago
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