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3 years ago

What’s the square root of 15

Mathematics

2 answers:

viva [34]3 years ago

4 0

Answer:3.87298334621

Step-by-step explanation:

Mumz [18]3 years ago

3 0

Answer:

square root of 15 is 3.87 or 3.9 when rounded to nearest tenth

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Given that f(x) = x2 – 5x – 14 and g(x) = x – 7, find (f +g)(x) and

Angelina_Jolie [31]

Answer:

$(f+g)(x)=x^2-4x-21$

Step-by-step explanation:

We are given:

$f(x)=x^2-5x-14\text{ and } g(x)=x-7$

And we want to find:

$(f+g)(x)$

This is equivalent to:

$=f(x)+g(x)$

Therefore, by substitution:

$=(x^2-5x-14)+(x-7)$

Rearranging gives:

$=(x^2)+(-5x+x)+(-14-7)$

Combine like terms:

$=x^2-4x-21$

6 0

3 years ago

Ryan buys some jumpers to sell on a stall.

Gemiola [76]

Answer:

£160

Step-by-step explanation:

£140÷60=£2.33

60×40%=24

£8×24=£192

60-24=36

36÷2=18

18÷2=9

9×£8=£72

9×(£8÷2)=£36

£192+£72+£36=£300

£300-£140=£160

8 0

2 years ago

Each day, Maya eats 1/5 cup of melons in the morning and 1/5 cup of melons in the afternoon. How many days will it take Maya to

blondinia [14]

Answer:

Step-by-step explanation:

If Maya eats 1/5 cups of melon twice a day: once in the morn n once in the afternoon, she eats 2/5 cups of melon a day.

8=2/5*d

d=# of days

8*5=2d

40/2=d

d=20

∴ Therefore it will take 20 days for Maya to eat 8 cups of melon.

4 0

3 years ago

What is the measure of ZABC?*

gtnhenbr [62]

Answer:

d)58

Step-by-step explanation:

21+37=58 add angles

8 0

2 years ago

Read 2 more answers

Consider the force field and circle defined below.

grin007 [14]

By Green's theorem,

$\displaystyle\int_{x^2+y^2=9}\vec F(x,y)\cdot\mathrm d\vec r=\iint_D\left(\frac{\partial(xy)}{\partial x}-\frac{\partial(x^2)}{\partial y}\right)\,\mathrm dx\,\mathrm dy=\iint_Dy\,\mathrm dx\,\mathrm dy$

where $C$ is the circle $x^2+y^2=9$ and $D$ is the interior of $C$ , or the disk $x^2+y^2\le1$ .

Convert to polar coordinates, taking

$\begin{cases}x=r\cos\theta\\y=r\sin\theta\end{cases}\implies\mathrm dx\,\mathrm dy=r\,\mathrm dr\,\mathrm d\theta$

Then the work done by $\vec F$ on the particle is

$\displaystyle\iint_Dy\,\mathrm dx\,\mathrm dy=\int_0^{2\pi}\int_0^3(r\sin\theta)r\,\mathrm dr\,\mathrm d\theta=\left(\int_0^{2\pi}\sin\theta\,\mathrm d\theta\right)\left(\int_0^3r^2\,\mathrm dr\right)=\boxed0$

4 0

2 years ago