The 10 tons should have 37.9% cement.
Let the 25% mixture be x tons
Then the 68% mixture will be (10 -x) tons.
Using formula for mixtures:
Let p for percentage and w for weight in tons.
p₁w₁ + p₂w₂ = pw
25*x + 68*(10-x) = 37.9*10
25x + 680 - 68x = 379
680 - 43x = 379
680 - 379 = 43x
301 = 43x
43x = 301
x = 301/43
x = 7
Recall that x, was for the 25% mixture, 7 tons.
a) For the 68% mixture, = 10 - x = 10 -7 = 3 tons.
b) For the 25% mixture = x = 7 tons.
<span>z2-z(z+3)+3z
=> z2 - z2 - 3z + 3z
=> 0
we can cancel the like terms if they have different signs ..
Hope it helps !!</span>
Answer:
ok
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Answer:
I think the answer is C if I'm wrong sorry its been two years since i last learnt this
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Answer:
1x
Step-by-step explanation:
