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nasty-shy [4]
3 years ago
13

Find values of x and y for which ABCD must be a parallelogram. The diagram is not to

Mathematics
2 answers:
Nutka1998 [239]3 years ago
8 0
3x-14=x+2
Add 14 to both sides.
3x=x+16
Subtract x from both sides.
2x=16
Divide by 2.
x=8

4y-7=y+11
Add 7 to both sides.
4y=y+18
Subtract y from both sides.
3y=18
Divide by 3.
y=6

The answer is d.

Zina [86]3 years ago
7 0
The answer is d. 

3x-14 = x-2     solve for x

4y-7 = y+11    solve for y
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fiasKO [112]
interior angle of a regular 18-gon.
It is easier to calculate the exterior angle of a regular polygon of n-sides (n-gon) by the relation
exterior angle = 360/n
For a 18-gon, n=18, so exterior angle = 360/18=20 °
The value of each interior angle is therefore the supplement, or
Interior angle = 180-20=160 degrees.

Naming of a 9-gon
A polygon with 9 vertices is called a nonagon (in English) or enneagon (French ennéagone, but the English version is sometimes used)
You had a good start with the correct answer.

Exterior angle of a 15-gon
The exterior angle of a 15-gon can be calculated using the relation given in the first paragraph, namely
Exterior angle = 360/15=24 degrees
4 0
3 years ago
What is equivalent to 4x-2=38
Tom [10]
2x4 is the answer to 4x-2=38
7 0
2 years ago
Hi, I really need help with my homework please help
8090 [49]
Number one is 68 you have to divide on this download photomath its better because all you have to do is take a picture and it shows you how to do it ;)
5 0
3 years ago
Read 2 more answers
Please Help me with these question. first person to help me gets brainliest!!!!
lara [203]

4) the distance between the x-values is 3 and the distance between the y-values is 4

3² + 4² = d²

9 + 16 = d²

25 = d²

√25 = d

5 = d

Answer: C

6)

d = \sqrt{(x2 - x1)^{2}  + (y2 - y1)^{2} }

d = \sqrt{(-2 - (-3))^{2}  + (2 - (-4))^{2} }

d = \sqrt{(-2 +3)^{2}  + (2 +4)^{2} }

d =  \sqrt{(1)^{2}  + (6)^{2} }

d =  \sqrt{1 + 36}

d = \sqrt{37}

d = 6.1

Answer: A

7 0
3 years ago
A vacant lot is being converted into a community garden. The garden and and a walkway around its perimeter have an area of 460 s
mariarad [96]

Answer:

The width of the walkway is 4 feet.

Step-by-step explanation:

The garden and a walkway around its perimeter have an area of 460 square feet.

The length of the garden = 15 feet

The width of the garden = 12 feet

Assuming that walkway is of uniform width, we can solve the following equation.

(12+2x)\times(15+2x)= 460

Expanding this we get;

4x^{2}+54x+180=460

=> 4x^{2}+54x-280=0

We will solve this using quadratic equation formula:

x=\frac{-b\pm \sqrt{b^{2} -4ac} }{2a}

Here a = 4 , b = 54 , c = -280

We get the roots as x = 4 and x = -\frac{35}{2}

Neglecting the negative value, we will take x = 4 feet.

Hence, the width of the walkway is 4 feet.

5 0
3 years ago
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