Answer:
46 housewives read all three magazines.
Step-by-step explanation:
Given:
n(A) = 150
n(B) = 200
n(C) = 156
n(A∩B) = 48
n(B∩C) = 60
n(A∩C) = 52
n(A∪B∪C) = 300
so we know the relation as:
n(A∪B∪C) = n(A) + n(B) + n(C) - n(A∩B) - n(B∩C) - n(A∩C) + n(A∩B∩C)
∴ n(A∩B∩C) = n(A) + n(B) + n(C) - n(A∩B) - n(B∩C) - n(A∩C) - n(A∪B∪C)
= 150 + 200+ 156 - 48 - 60 - 52 - 300
= 46
Hence the number of housewives that had read all three magazine is 46.
Step-by-step explanation:
Answer:
39
Step-by-step explanation:
just did 13 plus 13 plus 13
A system of equations is good for a problem like this.
Let x be the number of student tickets sold
Let y be the number of adult tickets sold
x + y = 200
2x + 3y = 490
x = 200 - y
2(200 - y) + 3y = 490
400 - 2y + 3y = 490
400 + y = 490
y = 90
The number of adult tickets sold was 90.
x + 90 = 200 --> x = 110
2x + 3(90) = 490 --> 2x + 270 = 490 --> 2x = 220 --> x = 110
The number student tickets sold was 110.
