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worty [1.4K]
2 years ago
9

If f(x)=3x, g(x)=x+4, and h(x)=x2-1, find the value of f[g(1)]

Mathematics
1 answer:
Strike441 [17]2 years ago
4 0

Answer:

15.

Step-by-step explanation:

The given functions are

f(x)=3x

f[g(1)]=f[(1)+4]

h(x)=x^2-1

We need to find the value of f[g(1)].

f[g(1)]=f[(1)+4]          [\because f[g(1)]=f[(1)+4]]

f[g(1)]=f[5]

f[g(1)]=3(5)           [\because f(x)=3x]

f[g(1)]=15    

Therefore, the value of f[g(1)] is 15.

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The answer is negative 14.

Step-by-step explanation:

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Find the values of k so that each remainder is three. <br> 10. (x^2+ 5x + 7) = (x + k)
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Answer:

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Step-by-step explanation:

We can use the Polynomial Remainder Theorem. It states that if we divide a polynomial P(x) by a <em>binomial</em> in the form (x - a), then our remainder will be P(a).

We are dividing:

(x^2+5x+7)\div(x+k)

So, a polynomial by a binomial factor.

Our factor is (x + k) or (x - (-k)). Using the form (x - a), our a = -k.

We want our remainder to be 3. So, P(a)=P(-k)=3.

Therefore:

(-k)^2+5(-k)+7=3

Simplify:

k^2-5k+7=3

Solve for <em>k</em>. Subtract 3 from both sides:

k^2-5k+4=0

Factor:

(k-1)(k-4)=0

Zero Product Property:

k-1=0\text{ or } k-4=0

Solve:

k=1\text{ or } k=4

So, either of the two expressions:

(x^2+5x+7)\div(x+1)\text{ or } (x^2+5x+7)\div(x+4)

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Answer:

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Step-by-step explanation:

Nah dude, you got it. :)

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