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blagie [28]
3 years ago
12

An object accelerates to a velocity of 34m/s over a time 13 s the acceleration it experience was 15 m/s2 what was it’s intital v

elocity
Physics
1 answer:
miv72 [106K]3 years ago
7 0
Vf =Vi + at
Vi =Vf - at
= 34 - 15•13
= - 161 m/s :/
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Sensory receptors pick up on senses from outside the body. To respond to the sense, what path does the information follow?
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Explanation:

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2 years ago
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How should the student use the data collected and the known quantities from the experiment to determine the initial total mechan
fiasKO [112]

It should be noted that the student should use K = 1/2mv² with the initial speed of the block for one trial.

<h3>Method of using the data collected.</h3>

From the complete information, the student wants to use the data collected and the known quantities from the experiment to determine the initial total mechanical energy of the block-ramp-Earth system for all trials in the experiment.

In this case, it's important to use K = 1/2mv² with the block's initial speed for one trial due to the fact that the initial speed is the same in all the trials.

Learn more about experiments on:

brainly.com/question/17274244

7 0
2 years ago
In many cartoon shows, a character runs of a cliff, realizes his predicament and lets out a scream. He continues to scream as he
Rzqust [24]

Answer:

Increasing until terminal velocity is reached

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5 0
3 years ago
If the work done to stretch an ideal spring by 4.0 cm is 6.0 j, what is the spring constant (force constant) of this spring?
Alisiya [41]

Answer:

The spring constant is 3750 N/m  

Explanation:

Use the following two relationships:

(Work) = (Force) x (Displacement)

(Force) = (Spring constant) x (Displacement)

=>

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4 0
3 years ago
The equation r (t )=(2t + 4)⋅i + (√ 7 )t⋅ j + 3t ²⋅k the position of a particle in space at time t. Find the angle between the v
velikii [3]

Answer:

\theta = n\pi/2, {\rm where~n~is~an~integer.}

Explanation:

We should first find the velocity and acceleration functions. The velocity function is the derivative of the position function with respect to time, and the acceleration function is the derivative of the velocity function with respect to time.

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Similarly,

\vec{a}(t) = \frac{d\vec{v}(t)}{dt} = (6)\^k

Now, the angle between velocity and acceleration vectors can be found.

The angle between any two vectors can be found by scalar product of them:

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So,

\vec{v}(t).\vec{a}(t) = |\vec{v}(t)|.|\vec{a}(t)|.\cos(\theta)\\36t = \sqrt{4 + 7 + 36t^2}.6.\cos(\theta)

At time t = 0, this equation becomes

0 = 6\sqrt{11}\cos(\theta)\\\cos(\theta) = 0\\\theta = n\pi/2, {\rm where~n~is~an~integer.}

7 0
3 years ago
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