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blagie [28]
3 years ago
12

An object accelerates to a velocity of 34m/s over a time 13 s the acceleration it experience was 15 m/s2 what was it’s intital v

elocity
Physics
1 answer:
miv72 [106K]3 years ago
7 0
Vf =Vi + at
Vi =Vf - at
= 34 - 15•13
= - 161 m/s :/
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Two sources of light of wavelength 700 nm are 9 m away from a pinhole of diameter 1.2 mm. How far apart must the sources be for
Lelechka [254]

Answer:

The distance is  D  =  0.000712 \ m

Explanation:

From the question we are told that

    The wavelength of  the  light source is  \lambda  =  700 \ nm = 700 *10^{-9} \  m

     The distance from a pin hole is  x  =  9\ m

       The  diameter of the pin  hole is  d =  1.2 \ mm  =  0.0012 \ m

     

Generally the distance which the light source need to be in order for their diffraction patterns to be resolved by Rayleigh's criterion is

mathematically represented as

              D  =  \frac{1.22 \lambda }{d }

substituting values

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3 years ago
A charged particle of mass m = 5.00g and charge q = -70.0μC moves horizontally to the right at a constant velocity of v = 30.0 k
pychu [463]

Answer:

The magnitude of the force, B = 5 Tesla, Up (North) direction

Explanation:

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where B is the magnetic field

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B = 5.0 Teslas

The force on a negative charge is in exactly the opposite direction to that on a positive charge.

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